Top 100+ Chain Rule Aptitude Problems with Solutions - 1

Question: 1

On a scale of map, 0.6 cm represents 6.6 km. if the distance between the points on the map is 80.5 cm, the actual distance between these points is

(A) 72.5 km

(B) 190.75 km

(C) 885.5 km

(D) 955.5 km

Ans: C

Let the actual distance be x km. Then,

More distance on the map, More is the actual distance
(Direct Proportion)

∴ 0.6 : 80.5 : : 66 : x

⇔ 0.6 x = 80.5 × 6.6

⇔ x = $${80.5 × 6.6} / {0.6}$$

⇔ x = 885.5.

Question: 2

A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions made by the larger wheel is

(A) 4

(B) 5

(C) 7

(D) 9

Ans: D

Let the required number of revolutions made by larger wheel be x.

Then, More cogs, Less revolutions
(Indirect Proportion)

∴ 14 : 6 : : 21 : x

⇔ 14 × x = 6 × 21

⇔ x = $$({6 × 21} / {14})$$ = 9.

Question: 3

In a camp, there is a meal for 120 men or 200 children. If 150 children had taken the meal, how many men will be catered to with the remaining meal?

(A) 10

(B) 20

(C) 30

(D) 40

Ans: C

There is a meal for 200 children. 150 children have taken the meal.

Remaining meal is to created to 50 children.

Now, 200 children = 120 men

50 children = $$({120} /{200} × 50)$$ men = 30 men.

Question: 4

A rope makes 70 rounds of the circumference of a cylinder whose radius of the base is 14 cm. How many times can it go round a cylinder with radius 20 cm?

(A) 40

(B) 42

(C) 49

(D) 100

Ans: C

Let the required number of rounds be x.

More radius, Less rounds

(Indirect Proportion)

∴ 20 : 14 : : 70 : x ⇔ (20 × x) = (14 × 70)

⇔ x = $${14 × 70} / {20}$$ ⇔ x = 49.

Question: 5

A certain number of men can finish a piece of work in 100 days. If there were 10 men less, it would take 10 days more for the work to be finished. How many men were there originally?

(A) 70

(B) 80

(C) 110

(D) 120

Ans: C

Originally, let there be x men.

Less men, More days
(Indirect Proportion)

∴ (x – 10) : x : : 100 : 110 ⇔ (x – 10) × 110 – x × 100 ⇔ 10 x = 1100
⇔ x = 110.

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