1000+ SSC Aptitude Questions and Answers - 1

Ans: A

A : B = 100 : 75 and B : C = 100 : 96.

∴ A : C = $$({A}/{B} × {B}/{C})$$ = $$(100/75 × 100/96)$$ = $${100}/{72}$$ = 100 : 72.

A beats C by (100 – 72) = 28 m.

Ans: C

A : B = 1000 : 900, B : C = 400 : 360 = 100 : 90 = 900 : 810

⇒ A : B : C = 1000 : 900 : 810

⇒ A : C = 1000 : 810 = 500 : 405

⇒ In a 500 m race, A beats C by (500 – 405) m = 95 m.

Ans: C

In a km race, suppose A takes t sec.

Then B, takes (t + 30) sec. and C takes (t + 45) sec.

180 m is covered by C in 45 sec.

∴ 1000 m is covered by C in $$({45}/{180} × 1000)$$ sec = 250 sec.

∴ A covers 1000 m in (250 – 45) sec = 205 sec.

Ans: C

B : A = 200 : 190 and C : B = 200 : 180

∴ $${C}/{A}$$ = $$({C}/{B} × {B}/{A})$$ = $$(200/180 × 200/190)$$ = $${200}/{171}$$.

∴ C can give to A, a start of (200 – 171) m = 29 m.

Ans: B

Time taken by A to cover 100 m = $$({60 × 60} / {8000} × 100)$$sec = 45 sec.

∴ B covers (100 – 5) m = 95 m in (45 + 15) sec = 60 sec.

∴ B’s speed = $$({95}/{60})$$m/sec = $$({95/60} × {18/5})$$km/hr = $${57}/{10}$$km/hr = 5.7 km/hr.