100+ Problems on Time and Distance with Solutions Pdf - 1
Question: 1
A train covers a certain distance in 50 minutes, if it runs at a speed of 48 km/hr on an average. The speed at which the train must run to reduce the time of journey to 40 minutes, will be
(A) 40 km/hr
(B) 50 km/hr
(C) 60 km/hr
(D) 70 km/hr
Ans: C
Time = $$({50} / {60})$$ hour = $${5} / {6}$$ hour
Speed = 48 km/hr
∴ Distance = $$(48 × {5} / {6})$$ km = 40 km.
Now, distance = 40 km.
And time = $$({40} / {60})$$ hour = $${2} / {3}$$ hour
∴ New speed = $$(40 × {3}/{2})$$ km/hr = 60 km/hr.
Question: 2
A motorists travelled between two towns, which are 65 km apart, in 2 hours and 10 minutes. Find the speed in metres per minute.
(A) 200
(B) 300
(C) 400
(D) 500
Ans: D
Distance covered = 65 km = 65000 m.
Time taken = 2 hrs 10 min =[( 2 × 60) + 10]min = 130 min.
∴ Speed = $$({65000} / {130})$$m/min = 500 m/min.
Question: 3
The mileage of a motorbike A and motorbike B is 42 km per litre and 52 km per litre respectively. Motorbike A covered 294 km and motorbike B covered 208 km. If the cost of 1 litre of petrol is Rs.48, how much amount would be spent on petrol to cover the total distance by both the motor bikes together?
(A) Rs.480
(B) Rs.518
(C) Rs. 528
(D) Rs. 576
Ans: C
Quantity of petrol consumed by both the motorbikes
= $$({294} / {42} + {209} / {52})$$ litres = 11 litres.
∴ Total amount spent on petrol = Rs. (48 × 11) = Rs. 528.
Question: 4
A man takes 50 minutes to cover a certain distance at a speed of 6 km/hr. If he walks with a speed of 10 km/hr, he covers the same distance in
(A) 10 minutes
(B) 20 minutes
(C) 30 minutes
(D) 40 minutes
Ans: C
Distance = Speed × Time = $$(6 × {50} / {60})$$km = 5 km.
∴ Required time = $${Distance} / {Speed}$$ = $$({5} / {10})$$ hrs = $${1} / {2}$$ hr = 30 min.
Question: 5
An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in $$1{2} / {3}$$ hours, it must travel at a speed of
(A) 300 kmph
(B) 360 kmph
(C) 720 kmph
(D) 920 kmph
Ans: C
Distance = (240 × 5)km = 1200 km.
∴ Required speed = $$(1200 × {3} / {5})$$km/hr = 720 km/hr.
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