Top 10,000+ Aptitude Online Test - 1

Ans: D

Let the number be x and y.

Then, 2x + 3y = 39 -----------(i)

And 3x + 2y = 36 -------(ii)

On solving (i) and (ii), we get : x = 6 and y = 9.

∴ Larger number = 9.

Ans: C

Let the ten’ digit be x and unit’ digit be y.

Then, 10x + y = 3(x + y) ⇒ 7x - 2y = 0

10x + y + 45 = 10y + x ⇒ y - x = 5

Solving (i) and (ii) we get x = 2 an y = 7.

∴ Required number = 27.

Ans: C

A : B = 2 : 3 and B : C = 5 : 3 = $${3}/{5} × 5$$ : $${3}/{5} × 3$$ = $$3 : {9}/{5}$$

So, A : B : C = 2 : 3 : $${9}/{5}$$ = 10 : 15 : 9.

∴ Second number = $$(136 × {15}/{34})$$ = 60.

Ans: b

Let the five successive odd number be x, x + 2, x + 4, x + 6, x + 8

Then, according to given information

185 = x + x + 2 + x + 4 + x + 6 + x + 8

⇒ 185 = 5x + 20

⇒ 5x = 185 - 20 = 165

⇒ x = 33.

Highest number = 33 + 8 = 41.

Ans: C

Let the number be x.

Then, $$x × {2}/{3} x$$ = 864

⇔ $${2}/{3}$$x² = 864

⇔ x² = $$(864 × 3 / 2)$$ = 1296 ⇔ x = $$√1296$$ = 36.