1000+ Amhara Bank Exam Questions and Answers Pdf - 1

Question: 1

A alone can complete a piece of work in 8 days. Work done by B alone in one day is half of the work done by A alone in one day. In how many days can the work be completed if A and B work together?

(A) $$5{1}/{2}$$

(B) $$5{1}/{3}$$

(C) $$6{1}/{2}$$

(D) $$6{1}/{3}$$

Ans: B

A does the work in 8 days.

B does the work in 16 days.

∴ A + B do the work in $${8 × 16} / {8 + 16}$$ = $${16}/{3}$$ = $$5{1}/{3}$$ days.

Question: 2

A can complete a piece of work in 12 days. A and B together can complete the same piece of work in 8 days. In how many days can B alone complete the same piece of work?

(A) 15 days

(B) 16 days

(C) 18 days

(D) 24 days

Ans: D

Work of A for 1 day = $${1}/{2}$$

Work of (A + B) for 1 day = $${1}/{8}$$

∴ Work of B for 1 day = $${1}/{8} – {1}/{12}$$ = $${1}/{24}$$

∴ B alone can complete the same work in 24 days.

Question: 3

15 men can do a piece of work in 6 days. How many men would be required to do the same work in 7.5 days?

(A) 10

(B) 12

(C) 16

(D) 18

Ans: B

Required men = $$15({6}/{7.5})$$ = 12.

Question: 4

A can complete a piece of work in 12 days. A and B together can complete the same piece of work in 4 days. In how many can B alone complete the same piece of work?

(A) 2 days

(B) 6 days

(C) 10 days

(D) 12 days

Ans: B

Suppose the work consists of making 12 pillars. Since A can complete the work in 12 days, this implies that A can make one pillar in a day. Similarly, we get that A and B together can make three pillars in a day. Hence we can conclude that ‘B’ can make two pillars in a day. Hence, the total work (12 pillars) can be completed by B in (12 &divde; 2) = 6 days.

Question: 5

A and B can together finish a work in 30 days. They worked together for 20 days and then B left. After another 20 days A finished the remaining work. In how many days can A alone finish the job?

(A) 50 days

(B) 60 days

(C) 70 days

(D) 80 days

Ans: B

A and B together do $${20}/{30}$$ = $${2}/{3}$$ part of the work in 20 days.

Remaining work = $$1 - {2}/{3}$$ = $${1}/{3}$$

∴ A alone can do the work in 20 × 3 = 60 days.

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