1000+ Bank of Nova Scotia Aptitude Test Questions & Answers - 1
Question: 1
A person divided Rs.10800 among his three sons in the ratio 3 : 4 : 5. Second son kept Rs.1000 for himself, gave Rs.600 to his wife and divided the remaining money among his two daughters in the ratio 11 : 9. Then one of his daughters received
(A) Rs.1000
(B) Rs.1050
(C) Rs.1100
(D) Rs.1150
Ans: C
Second son’s share = Rs.$$(10800 × {4}/{12})$$ = Rs.3600.
Money distributed between the two daughters
= Rs.[3600 – (1000 + 600)] = Rs.2000.
First daughter’s share = Rs.$$(2000 × {11}/{20})$$ = Rs.1100.
Second daughter’s share = Rs.$$(2000 × {9}/{20})$$ = Rs. 900.
Question: 2
The sum of three numbers is 116. The second number and the third number are in the ratio of 9 : 16 while the first number and the third number are in the ratio of 1 : 4. Find the second number.
(A) 8
(B) 16
(C) 36
(D) 64
Ans: C
Second : Third = 9 : 16,
Third : First = 4 : 1 = 16 : 4.
∴ Second : Third : First = 9 : 16 : 4.
Second number = $$(116 × {9}/{29})$$ = 36.
Question: 3
Two numbers are in the ratio 4 : 5 and their L.C.M. is 180. The smaller number is
(A) 15
(B) 36
(C) 45
(D) 54
Ans: B
Let the numbers be 4x and 5x.
Then, their L.C.M. = 20x.
20x = 180 or x = 9.
∴ Smaller number = 4x = 4 × 9 = 36.
Question: 4
Three numbers A, B and C are in the ratio 1 : 2 : 3. Their average is 600. If A is increased by 10% and B is decreased by 20%, then to get the average increased by 5%, C will be increased by
(A) 100
(B) 180
(C) 240
(D) 360
Ans: B
Let A = x, B = 2x, C = 3x. Then, $${x + 2x + 3x} / {3}$$ = 600
⇒ 2x = 600 ⇒ x = 300.
So, A = 300, B = 600, C = 900.
New value of A = 110% of 300 = 330.
New value of B = 80% of 600 = 480
New average = 105% of 600 = 630.
New value of C = (630 × 3) - (330 + 480) = 1080.
∴ Increase in value of C = (1080 - 900) = 180.
Question: 5
Mr. Sharma’s expenditure and savings are in the ratio of 3 : 2. His income increases by 10%. How expenditure also increases by 12%. How much percent does his savings increase?
(A) 6%
(B) 7%
(C) 11%
(D) 13%
Ans: B
Let Mr. Sharma’s expenditure be Rs.3x and his savings be Rs.2x.
Income = Rs.(3x + 2x) = Rs.5x.
Increased income = 110% of Rs.5x = Rs.5.5x.
Increased expenditure = 112% of Rs.3x = Rs.3.36x.
Increased savings = Rs.(5.5x - 3.36x) = Rs.2.14x.
Increase in savings = Rs.(2.14 - 2) x = Rs.0.14x.
∴ Increase % = $$({0.14}/{2x} × 100)$$% = 7%.
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