100+ Chain Rule Aptitude Questions and Answers Pdf - 1
Question: 1
A flagstaff 17.5 m high casts a shadow of length 40.5 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be
(A) 10 m
(B) 11.5 m
(C) 12.5 m
(D) 17.5 m
Ans: C
Let the height of the building be x metres.
Less lengthy shadow, Less is the height (Direct Proportion)
∴ 40.25 : 28.75 : : 17.5 : x
⇔ 40.25 × x = 28.75 × 17.5
⇔ x = $(28.75 × 17.5)/{40.25}$ ⇔ x = 12.5.
Question: 2
Some persons can do a piece of work in 12 days. Two times the number of such persons will do half of that work in
(A) 3 days
(B) 4 days
(C) 5 days
(D) 6 days
Ans: A
Let x men can do the work in 12 days and the required number of days be z.
More men, Less days (Indirect Proportion)
Less work, Less days (Direct Proportion)
| Men | 2x : x | |
| : : 12 : z | ||
| Work | 1 : $1/2$ |
∴ (2x × 1 × z) = $(x × 1/2 × 12)$
⇔ 2xz = 6x ⇔ z = 3.
Question: 3
A mat weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat weavers in 8 days?
(A) 8
(B) 12
(C) 16
(D) 20
Ans: C
Let the required number of mats be x.
More weavers, More mats (Direct Proportion)
More days, More mats (Direct Proportion)
| Weavers | 4 : 8 | |
| : : 4 : x | ||
| Days | 4 : 8 |
∴ 4 × 4 × x = 8 × 8 × 4 ⇔ x = $(8 × 8 × 4)/(4 × 4)$ = 16.
Question: 4
A garrison of 500 men had provisions for 27 days. After 3 days a reinforcement of 300 men arrived. For how many more days will the remaining food last now?
(A) 12
(B) 15
(C) 18
(D) 21
Ans: B
Let the remaining food last for x days.
500 men had provisions for (27 - 3) = 24 days.
(500 + 300) men had provisions for x days.
More men, Less days (Indirect Proportion)
∴ 800 : 500 : : 24 : x
⇔ (800 × x) = (500 × 24)
⇔ x = $({500 × 24}/800)$ = 15.
Question: 5
If a quarter kg of potato costs 60 paise, how many paise will 200 gm cost?
(A) 42 paise
(B) 44 paise
(C) 48 paise
(D) 54 paise
Ans: C
Let the required cost be x paise.
Less weight, Less cost (Direct Proportion)
∴ 250 : 200 : : 60 : x
⇔ 250 × x = (200 × 60)
⇔ x = $(200 × 60)/250$ ⇔ x = 48.
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