# 100+ Chain Rule Aptitude Questions and Answers Pdf - 1

Question: 1

A flagstaff 17.5 m high casts a shadow of length 40.5 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be

(A) 10 m

(B) 11.5 m

(C) 12.5 m

(D) 17.5 m

Ans: C

Let the height of the building be x metres.

Less lengthy shadow, Less is the height (Direct Proportion)

∴ 40.25 : 28.75 : : 17.5 : x

⇔ 40.25 × x = 28.75 × 17.5

⇔ x = \$(28.75 × 17.5)/{40.25}\$ ⇔ x = 12.5.

Question: 2

Some persons can do a piece of work in 12 days. Two times the number of such persons will do half of that work in

(A) 3 days

(B) 4 days

(C) 5 days

(D) 6 days

Ans: A

Let x men can do the work in 12 days and the required number of days be z.

More men, Less days (Indirect Proportion)

Less work, Less days (Direct Proportion)

 Men 2x : x : : 12 : z Work 1 : \$1/2\$

∴ (2x × 1 × z) = \$(x × 1/2 × 12)\$

⇔ 2xz = 6x ⇔ z = 3.

Question: 3

A mat weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat weavers in 8 days?

(A) 8

(B) 12

(C) 16

(D) 20

Ans: C

Let the required number of mats be x.

More weavers, More mats (Direct Proportion)

More days, More mats (Direct Proportion)

 Weavers 4 : 8 : : 4 : x Days 4 : 8

∴ 4 × 4 × x = 8 × 8 × 4 ⇔ x = \$(8 × 8 × 4)/(4 × 4)\$ = 16.

Question: 4

A garrison of 500 men had provisions for 27 days. After 3 days a reinforcement of 300 men arrived. For how many more days will the remaining food last now?

(A) 12

(B) 15

(C) 18

(D) 21

Ans: B

Let the remaining food last for x days.

500 men had provisions for (27 - 3) = 24 days.

(500 + 300) men had provisions for x days.

More men, Less days (Indirect Proportion)

∴ 800 : 500 : : 24 : x

⇔ (800 × x) = (500 × 24)

⇔ x = \$({500 × 24}/800)\$ = 15.

Question: 5

If a quarter kg of potato costs 60 paise, how many paise will 200 gm cost?

(A) 42 paise

(B) 44 paise

(C) 48 paise

(D) 54 paise

Ans: C

Let the required cost be x paise.

Less weight, Less cost (Direct Proportion)

∴ 250 : 200 : : 60 : x

⇔ 250 × x = (200 × 60)

⇔ x = \$(200 × 60)/250\$ ⇔ x = 48.

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