Top 100+ Compound Interest Questions and Answers - 1

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Question: 1

What will be the difference between simple and compound interest @ 10% per annum on a sum of Rs. 1000 after 4 years?

(A) Rs. 31

(B) Rs. 40.40

(D) Rs. 74.20

View Answer

Ans: C

S.I. = Rs. $$({1000 × 10 × 4} / {100})$$ = Rs. 400.

C.I. = Rs. $$[1000 × (1 + {10}/{100})^4 - 1000]$$ = Rs. 464.10.

Difference = Rs. (464.10 – 400) = 64.10.

Question: 2

The simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is

(A) Rs. 1550

(B) Rs. 1650

(D) Rs. 1750

View Answer

Ans: D

C.I. = Rs. $$[4000 × (1 + {10} / {100})^2 - 4000]$$

= Rs. $$(4000 × {11} /{10} × {11} / {10} – 4000)$$ = Rs. 840.

∴ Sum = Rs. $$({420 × 100} / {3 × 8})$$ = Rs. 1750.

Question: 3

The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half yearly is

(A) 6%

(B) 6.07%

(D) 6.10%

View Answer

Ans: C

Amount of Rs. 100 for 1 year when compounded half yearly

= Rs. $$[100 × (1 + {3} /{100})^2]$$ = Rs. 106.09.

∴ Effective rate = (106.09 – 100)% = 6.09%.

Question: 4

The difference between simple interest and compound interest on Rs. 1200 for one year at 10% per annum reckoned half yearly is

(A) Rs. 3

(B) Rs. 3.25

(D) Rs. 4

View Answer

Ans: A

S.I. = Rs. $$({1200 × 10 × 1} / {100})$$ = Rs. 120.

C.I. = Rs. $$[1200 × (1 + 5 / 100)^2 - 1200]$$ = Rs. 123.

Difference = Rs. (123 – 120) = Rs. 3.

Question: 5

What will be the compound interest accrued on an amount of Rs. 10000 % 20 p.c.p.a. in 2 years if the interest is compound half yearly?

(A) Rs. 4600

(B) Rs. 4641

(D) Rs. 4820

View Answer

Ans: B

P = Rs. 10000, R = 20%, p.a. = 10% per half year.

T = 2 years = 4 half years.

Amount = Rs. [10000 × $$(1 + {10} / {100})^4$$]

= Rs. $$(10000 × {11} / {10} × {11} / {10} × {11} / {10} × {11] / {10})$$ = Rs. 14641.

∴ C.I. = Rs. (14641 – 10000) = Rs. 4641.

Top 100+ Compound Interest Questions and Answers - 1

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