# 100+ Tabulation Questions for Bank Exams - 1

Question: 1

Study the given table carefully and answer the questions that follow.
Number of candidates appeared and qualified for a test (in hundreds) in 6 different years from 5 different zones.
In which years was in zones the difference between the appeared candidates and qualified candidates the second lowest?

(A) 2005

(B) 2006

(C) 2007

(D) 2008

Ans: C

In zone S, the difference between the appeared candidates and the qualified candidates in various year is given below.

2005 → (4.2 – 2.4) = 1.8,

2006 → (7.4 – 3.3) = 4.1,

2007 → (8.3 – 5.6) = 2.7,

2008 → (9.3 – 6.4) = 2.9

2009 → (11.4 – 5.2) = 6.2,

2010 → (14.2 – 11.4) = 2.8

It was lowest in 2005 and second lowest in 2007.

Question: 2

The number of candidates who qualified the test from zone R in the year 2010 was approximately what percentage of the number of candidates who appeared from zone Q in the year 2008?

(A) 132

(B) 137

(C) 142

(D) 152

Ans: B

Required percentage = \$\$({7.4} / {5.4} × 100)\$\$% = \$\${3700} / {27}\$\$% = 137%.

Question: 3

What was the average number of candidates appeared from zone T over all the years together?

(A) 805

(B) 810

(C) 820

(D) 830

Ans: A

Average number of candidates appeared from T all over the years = \$\${(6.2 + 6.2 + 6.4 + 7.8 + 9.9 + 11.8) × 100} / {6}\$\$ = \$\${(48.3 × 100)} / {6}\$\$ = \$\${4830} / {6}\$\$ = 805.

Question: 4

What was the ratio of the number of candidates appeared from zone P in the year 2005 to the number of candidates qualified from zone S in the year 2007?

(A) 4 : 1

(B) 4 : 3

(C) 4 : 7

(D) 9 : 4

Ans: C

Required ratio = \$\${3.2} / {5.6}\$\$ = \$\${32} / {56}\$\$ = \$\${4} / {7}\$\$ = 4 : 7.

Question: 5

From which zone was the total number of candidates who qualified the test, the second highest in the year?

(A) P

(B) Q

(C) S

(D) T

Ans: D

Total number of candidates who qualified the test in 2009 and 2010 from various zones are

P → (4.8 + 5.6) = 10.4,

Q → (5.2 + 6.4) = 116,

R → (6.8 + 7.4) = 14.2.

S → (5.2 + 11.4) = 16.6,

T → (6.9 + 9.4) = 16.3.

It was highest from zone S and second highest from zone T.

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