1000+ HSBC Aptitude Questions and Answers Pdf - 1

Ans: A

Let the numbers be 3x and 4x.

Then, (4x)² = 8 × (3x)² - 224

⇔ 16x² = 72x² - 224

⇔ 56x² = 224 ⇔ x² = 4.

⇔ x = 2.

So, the numbers are 6 and 8.

Ans: B

Let the numbers be x and y.

Then, x + y = 25 and x - y = 13.

4xy = (x + y)² - (x - y)²

= (25)² - (13)²

= 625 - 169

= 456

⇒ xy = 114.

Ans: D

Let the six number be x, x + 1, x + 2, x + 3, x + 4 and x + 5.

Then, x + (x + 1) + (x + 2) = 27 ⇒ 3x + 3 = 27.

Required sum = (x + 3) + (x + 4) + (x + 5)

= 3x + 12 = (3x + 3) + 9 = 27 + 9 = 36.

Ans: B

Let the number be x, x + 2 and x + 4.

Then, x + (x + 2) + (x + 4) = x + 20

⇔ 2x = 4 ⇔ x = 7.

∴ Middle number = x + 2 = 9.

Ans: C

Let the numbers be x, x + 1 and x + 2.

Then, x² + (x + 1)² + (x + 2)² = 2030

⇔ 3x² + 6x – 2025 = 0

⇔ x² + 2x – 675 = 0

⇔ (x + 27) (x – 25) = 0

⇔ x = 25.

∴ Middle number = (x + 1) = 26.