100+ How to Solve Clock and Calendar Questions - 1

Question: 1

If a clock takes 22 seconds to strike 12, how much time will it take to strike 6?

(A) 10 seconds

(B) 12 seconds

(C) 14 seconds

(D) 16 seconds

Ans: A

In order to hear 12 strikes, there are 11 intervals (12 - 1) and time of each interval is uniform.

Hence, time to hear each strike is $${22}/{11}$$ = 2 seconds.

Now, to hear six strikes, there are 6 - 1, i.e., 5 × 2 = 10 seconds.

Hence, it will take 10 seconds for a clock to strike 6.

Question: 2

How often are the hands of a clock at right angle everyday?

(A) 38 times

(B) 40 times

(C) 44 times

(D) 48 times

Ans: C

In every hour there are two positions in which hands are at right angle. Each of these positions is repeated 11 times in every 12 hours.

∴ In every 12 hours, hands are at right angles 11 + 11 = 22 times and in a day hands are at right angles 22 + 22 = 44 times.

Question: 3

On 8th February, 1995 it was Wednesday. The day of the week on 8th February 1994 was

(A) Tuesday

(B) Wednesday

(C) Thursday

(D) Monday

Ans: A

1994 was an ordinary year, so it had 1 odd day. So, the day on 8th February, 1995 is one day beyond the day on 8th February, 1994.

But, 8th February 1995 was Wednesday.

∴ 8th February, 1994 was Tuesday.

Question: 4

India got independence on August 15, 1947. What was the day of the week?

(A) Monday

(B) Friday

(C) Thursday

(D) Sunday

Ans: B

Auguts 15, 1947 = (1600 + 300 + 46) years + January 1 to August 15th of 1947

= (1600 + 300 + 46) years + 365 - August 16 to December 31 1947

= (1600 + 300 + 46) years + (365 - 138) days

Number of odd days = 0 + 1 + 1 (from 11 leap years and 35 ordinary years) + 3 = 5 odd days.

∴ The day was Friday.

Question: 5

At what time between 4.30 and 5 will the hands of a clock be in a straight line?

(A) 42 minutes. past 4

(B) 46 minutes. past 4

(C) 50 minutes. past 4

(D) $$54 {6}/{11}$$minutes. past 4

Ans: D

At 4’o clock hands are 20 minutes spaces apart.

At time between 4.30 and 5 the hands will be in straight line when they point in opposite directions and there is a space of 30 minutes between them.

So, to be in this position minute hand has to gain 30 + 20 = 50 minutes spaces.

Minute hand gains, 50 minutes in $${60}/{55} × 50$$ = $$54{6}/{11}$$ minutes.

∴ Required time = $$54{6}/{11}$$ minutes past 4.

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