1000+ Infosys Aptitude Questions and Answers Pdf - 1

Question: 1

The least perfect square number divisible by 3, 4, 5, 6 and 8 is

(A) 1200

(B) 2400

(C) 3600

(D) 4800

Ans: C

L.C.M. of 3, 4, 5, 6, 8 is 120. Now, 120 = 2 × 2 × 2 × 3 × 5.

To make it a perfect square, it must be multiplied by 2 × 3 × 5.

So, required number = 22 × 22 × 32 × 52 = 3600.

Question: 2

The least number by which 1470 must be divided to get a number which is a perfect square, is

(A) 5

(B) 10

(C) 30

(D) 40

Ans: C

1470 = 7 × 7 × 5 × 6.

To make it a perfect square, it must be divided by 5 × 6, i.e., 30.

Question: 3

A group of students decided to collect as many paise from each member of the group as is the number of member. If the total collection amounts to R.59.29, the number of members in the group is

(A) 54

(B) 67

(C) 77

(D) 87

Ans: C

Money collected = (59.29 × 100) paise = 5929 paise.

∴ Number of members = $$√5929$$ = 77.

Question: 4

By what least number must 2600 be multiplied so as to make it a perfect cube?

(A) 5

(B) 7

(C) 10

(D) 14

Ans: C

21600 = 25 × 33 × 52.

To make it a perfect cube, it must be multiplied by (2 × 5) i.e., 10.

Question: 5

$$√ ?$$ + 14 = $$√2601$$

(A) 961

(B) 1225

(C) 1369

(D) 1521

Ans: C

Let the number be x.

Given $$√x$$ + 14 = $$√2601$$

or, $$√x$$ = 51 - 14 = 37

or x = 372 = 1369

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