# 100+ Line Charts Data Interpretation Questions and Answers - 1

Study the following graph carefully and answer the questions that follow. Question: 1

What was the ratio between the number of girls enrolled in School C in the year 2011 and the total number of girls enrolled in School A and School B together in the same year?

(A) 3 : 11

(B) 4 : 7

(C) 4 : 11

(D) 11 : 3

Ans: C

Required ratio = 20000 : (25000 + 30000)

= 20000 : 55000 = 20 : 55 = 4 : 11.

Question: 2

In which year was the total number of girls enrolled in all the three schools together second highest?

(A) 2008

(B) 2010

(C) 2011

(D) 2012

Ans: C

Total number of girls enrolled in all the three schools in various years (in thousands)

2008 → (20 + 15 + 10) = 45

2009 → (15 + 22.5 + 25) = 62.5

2010 → (27.5 + 15 + 20) = 62.5

2011 → (25 + 30 + 20) = 75

2012 → (30 + 25 + 27.5) = 82.5.

Clearly, it was second highest in 2011.

Question: 3

In which school was the difference between the number of girls enrolled in the year 2012 and 2008 minimum?

(A) Only School A

(B) Only School B

(C) Only School C

(D) Both School A and School B

Ans: D

Difference between the number of girls enrolled in 2012 and 2008 (in thousands) :

A → (30 – 20) = 10;

B → (25 – 15) = 10;

C → (27.5 – 10) = 17.5

So, it was minimum in both A and B.

Question: 4

What was the approximate average number of girls enrolled in the year 2010 in all the three schools together?

(A) 20000

(B) 20800

(C) 21600

(D) 22500

Ans: B

Required average = \$\${1}/{3}(27.5 + 15 + 20)\$\$ thousands

= \$\$({62.5} / {3} × 1000)\$\$ = \$\${62500} / {3}\$\$

= 20833 = 20800(approx.)

Question: 5

Total number of girls enrolled in all the three schools in the year 2008 was what percentage of the number of girls enrolled in School C in the year 2011?

(A) 165%

(B) 225%

(C) 240%

(D) 260%

Ans: B

Required percentage = \$\$[{(20 + 15 + 10) × 1000} / {20 × 1000} × 100]\$\$%

= \$\$[{45}/{20} × 100]\$\$% = 225%.

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