1000+ Cooperative Bank of Oromia Aptitude Test - 1

Question: 1

Two boys are running on two different circular paths with same centre. If their radii are 5 m and 10 m, the maximum possible distance between them is

(A) 5 m

(B) 10 m

(D) 20 m

View Answer

Ans: C

Since the diameter is the longest chord of a circle, so maximum possible distance = (10 + 5) m = 15 m.

Question: 2

Four equal sized maximum circular plates are cutoff from a square paper sheet of area 784 cm². The circumference of each plate is

(A) 22 cm

(B) 44 cm

(D) 88 cm

View Answer

Ans: B

Side of square paper = $$√784 cm$$ = 28 cm.

Radius of each circular plate = $$({1}/{4} × 28)$$ cm = 7 cm.

Circumference of each circular plate = $$(2× {22}/{7} × 7)$$ cm = 44 cm.

Question: 3

If a rectangle has length L and the width is one half of the length, then the area of the rectangle is

(A) L

(B) 2L

(D) $${1}/{2}L$$²

View Answer

Ans: D

Length = L, Width = $${L}/{2}$$

∴ Area = $$L × {L}/{2}$$ = $${1}/{2}L$$².

Question: 4

A rectangular parking space is marked out by painting three of its sides. If the length of the unpainted side is 9 feet, and the sum of the lengths of the painted sides is 37 feet, then what is the area of the parking space in square feet?

(A) 46

(B) 81

(D) 252

View Answer

Ans: C

Clearly, we have : l = 9 and l + 2b = 37 or b = 14.

∴ Area = ( l × b) = (9 × 14) sq.ft = 126 sq.ft.

Question: 5

What will be the cost of gardening 1 metre broad boundary around a rectangular plot having perimeter of 340 metres at the rate of Rs.10 per square metre?

(A) Rs.1700

(B) Rs.3400

(D) Rs.6440

View Answer

Ans: C

2(l + b) = 340 (Given).

Area of the boundary = [(l + 2)(b + 2) - lb] = 2(l + b) + 4 = 344.

∴ Cost of gardening = Rs.(344 × 10) = Rs.3440.

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1000+ Cooperative Bank of Oromia Aptitude Test - 1

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