100+ Permutation and Combination Aptitude Questions and Answers - 2

Question: 6

In how many ways can a cricket eleven be chosen out of 14 players?

(A) 200

(B) 300

(C) 364

(D) 382

Ans: C

Required number of ways

= 14C11 = 14C(14-11) = 14C3 = $${14 × 13 × 12} / {3 × 2 × 1}$$ = 364.

Question: 7

Out of 5 women and 4 men, a committee of three members is to be formed in such a way that at least one member is a woman. In how many different ways can it be done?

(A) 76

(B) 78

(C) 80

(D) 82

Ans: C

Required number of ways = (5C1 × 4C2) + (5C2 × 4C1) + (5C3)

= $$(5 × {4 × 3}/{2 × 1})$$ + $$({5 × 4} / {2 × 1} × 4)$$ + $$({5 × 4 × 3} / {3 × 2 × 1})$$

= (30 + 40 + 10) = 80.

Question: 8

A committee of 5 members is to formed out of 3 trainees, 4 professors and 6 research associates. In how may different ways can this be done if the committee should have 2 trainees and 3 research associates?

(A) 20

(B) 40

(C) 60

(D) 80

Ans: C

Required number of ways

= (3C2 × 6C3) = (3C1 × 6C3)

= $$(3 × {6 × 5 × 4} / {3 × 2 × 1})$$ = 60.

Question: 9

In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?

(A) 43

(B) 53

(C) 63

(D) 73

Ans: C

Required no. of ways

= (7C5 × 3C2) = (7C2 × 3C1) =$${7 × 6} / {2 × 1} × 3$$ = 63.

Question: 10

A committee of 5 members is to be formed out of 3 trainees, 4 professors and 6 research associates. In how many different ways can this be done, if the committee should have 4 professors and 1 research associate or all 3 trainees and 2 professors?

(A) 12

(B) 13

(C) 14

(D) 16

Ans: C

Required number of ways = (4C4 × 6C1) + (3C3 × 4C2)

= (1 + 6) + $$(1 + {4 × 3} / {2})$$ = (7 + 7) = 14.

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