# Top 100+ Problems on Ages Aptitude Questions and Answers - 1

Question: 1

Meeta is two years older than Sunita. After six years the sum of their ages will be seven times their present age. Find out the age of Meeta

(A) 6 years

(B) 8 years

(C) 10 years

Ans: D

Let Sunita’s age = x.

Then Meeta’s age = x+ 2.

After six years the sum of their ages will be seven times.

Hence the given data are inadequate.

Question: 2

Sachin was twice as old as Ajay 10 years back. How old is Ajay today if Sachin will be 40 years old 10 years hence?

(A) 10 years

(B) 20 years

(C) 30 years

(D) 50 years

Ans: B

Sachin’s age today = 30 years.

Sachin’s age 10 year’s back = 20 years.

Ajay’s age 10 years back = 10 years.

Ajay’s age today = 20 years.

Hence B is the correct answer.

Question: 3

Two years ago a man was 6 times as old as his son. After 18 years, he will be twice as old as his son. Their present ages ( in years) are

(A) 31, 7

(B) 32, 7

(C) 34, 9

(D) 36, 11

Ans: B

Let son’s age 2 years ago be x.

Man’s age 2 years ago = 6x

2 (x + 2 + 18) = (6x + 2 + 18)

⇒ 4x = 20 ⇒ x = 5.

Their present ages are (6x + 2) and (x + 2).

i.e., 32 years and 7 years.

Question: 4

Five years ago, the total of the ages of a father and his son was 40 years. The ratio of their present ages is 4 : 1. What is the present age of the father?

(A) 20 years

(B) 30 years

(C) 40 years

(D) 50 years

Ans: C

Let son’s age = x. Then, father’s age = 4x.

Therefore, (9x – 5) + (4x – 5) = 40 ⇒ x = 10

Present age of father = 40 years.

Question: 5

Pushpa is twice as old as Rita was 2 years ago. If the difference of their ages be 2 years, how old is Pushpa today?

(A) 6 years

(B) 7 years

(C) 8 years

(D) 10 years

Ans: C

Let Rita’s age 2 years ago = x years.

Pushpa’s age now = 2x years.

Therefore, 2x – (x + 2) = 2 ⇒ x = 4.

Therefore, Pushpa’s age now = 8 years.

Hence C is the correct answer.

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