100+ Problems on Time and Distance Questions for Bank Exams - 2
Question: 6
A vehicle travels at the rate of 80 kmph. What distance will it travel in 15 minutes?
(A) 18000 metre
(B) 20000 metre
(C) 22000 metre
(D) 24000 metre
Ans: B
Speed of vehicle = 80 kmph
= $$({80 × 1000} / {60})$$m/min
= $$({4000} / {3})$$m/min
∴ Required distance x = $${4000} / {3} × 15$$ = 20000 meter.
Question: 7
Two cyclists starts on a circular track from a given point but in opposite directions with speeds of 7 m/sec and 8 m/sec respectively. If the circumference of the circles is 300 metres, after what time will they meet at the starting point?
(A) 50 sec
(B) 100 sec
(C) 300 sec
(D) 500 sec
Ans: C
Time taken by the two cyclists to cover one round of the track is $${300} / {7}$$ sec and $${300} / {8}$$ sec respectively.
∴ Required time = L.C.M. of $${300} / {7}$$ and $${300} / {8}$$ = 300 sec.
Question: 8
A man goes uphill with an average speed of 35 km/hr and comes down with an average speed of 45 km/hr/ The distance travelled in both the cases being the same, the average speed for the entire journey is
(A) $$36{3} / {5}$$ km/hr
(B) $$38{3} / {5}$$ km/hr
(C) $$39{3} / {8}$$ km/hr
(D) 40 km/hr
Ans: C
Average speed = $$({2 × 35 × 45} / {35 + 45})$$ km/hr = $$39{3} / {8}$$ km/hr
Question: 9
A car can finish a certain journey in 10 hours at a speed of 48 km/hr. In order to cover the same distance in 8 hours, the speed of the car must be increased by
(A) 6 km/hr
(B) 12 km/hr
(C) 15 km/hr
(D) 18 km/hr
Ans: B
Distance = (Speed x time) = (48 x 10) km = 480 km
Now, New time = 8 hours
∴ New speed = $$({Distance} / {time})$$ = $$({480} / {8})$$ km/hr = 60 km/hr
∴ Increase in speed = (60 - 48) km/hr = 12 km/hr.
Question: 10
A passenger train runs at the rate of 80 kmph. It starts from the station, 6 hours after a goods train leaves the station. The passenger train overtakes the goods train after 4 hours. The speed of goods train is
(A) 22 km/hr
(B) 32 km/hr
(C) 45 km/hr
(D) 64 km/hr
Ans: B
Let the speed of the goods train be x km/hr.
Then, relative speed = (80 – x) km/hr.
Distance covered by goods train in 6 hrs at x km/hr
= Distance covered by passenger train in 4 hrs at (80 – x)km/hr
⇒ 6x = 4(80 – x) ⇒ 10x = 320 ⇒ x = 32 km/hr.
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