100+ Square Root and Cube Root Aptitude Questions Answers - 2

Question: 6

Find the smallest number by which 5808 should be multiplied so that the product becomes a perfect square.

(A) 1

(B) 2

(C) 3

(D) 5

Ans: C

5808 = 2 × 2 × 2 × 2 × 3 × 11 × 11 = 22 × 22 × 3 × 112.

To make it a perfect square, it must be multiplied by 3.

Question: 7

A mobile company offered to pay the Indian Cricket Team as much money per run scored by the side as the total number it gets in a one dayer against Austalia. Which one of the following cannot be the total amount to be spent by the company in this deal?

(A) 21,904

(B) 56,169

(C) 1,01,761

(D) 1,21,108

Ans: D

Clearly, the required number must be a perfect square.

Since, a number having 8 as the unit’s digit cannot be a perfect square, so 1,21,108 is not a perfect square.

Question: 8

The smallest perfect square that is divisible by 7! is

(A) 19600

(B) 44100

(C) 176400

(D) 705600

Ans: C

7! = 7 × 6 × 5 × 4 × 3 × 2 × 1

= 7 × 2 × 3 × 5 × 22 × 3 × 2

= 24 × 32 × 5 × 7.

Thus, the smallest perfect square number which is divisible by 7! is

(24 × 32 × 5 × 7) × (5 × 7)

= 5040 × 35 = 176400.

Question: 9

A man born in the first half of the nineteenth century was x years old in the year x2. He was born in

(A) 1806

(B) 1812

(C) 1825

(D) 1836

Ans: A

Clearly, the man was born between 1800 and 1850.

The only perfect square number between 1800 and 1850 is 1849.

And 1849 = (43)2.

So, the man was 43 years old in 1849.

Thus, he was born in (1849 – 43) = 1806.

Question: 10

(15)2 + (18)2 - 20 = $$√x$$

(A) 22

(B) 23

(C) 529

(D) 279841

Ans: D

Let (15)2 + (18)2 - 20 = $$√x$$.

Then, $$√x$$ = 225 + 324 – 20 = 529.

⇔ x = (529)2 = 279841.

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