# 1000+ Wipro Aptitude Questions and Answers Pdf - 1

Question: 1

Rs.2010 are to be divided among A, B, C in such a way that it A gets Rs.5, then B must get Rs.12 and if B gets Rs.4, then C must get Rs.550. The share of C will exceed that of B by

(A) Rs.240

(B) Rs.270

(C) Rs.420

(D) Rs.470

Ans: B

A : B = 5 : 12

B : C = 4 : 5.50 = \$\$12 : 16.5 = 12 : {33}/{2}\$\$

A : B : C = \$\$5 : 12 : {33}/{2}\$\$ = 10 : 24 : 33.

Sum of ratio terms = 10 + 24 + 33 = 67.

C’s share = Rs.\$\$(2010 × {33}/{67})\$\$ = Rs.990.

B’s share = Rs.\$\$(2010 × {24}/{67})\$\$ = Rs.720.

Required difference = Rs.(900 - 720) = Rs.270.

Question: 2

Rs.1050 are divided among P, Q and R. The share of P is \$\${2}/{5}\$\$ of the combined share of Q and R. P gets

(A) Rs.200

(B) Rs.220

(C) Rs.300

(D) Rs.320

Ans: C

P = \$\${2}/{5}(Q + R)\$\$ ⇒ P : (Q + R) = 2 : 5.

∴ P’s share = Rs.\$\$(1050 × {2}/{7})\$\$ = Rs.300.

Question: 3

Two numbers are in the ratio 3 : 4. If the difference of their squares is 63, then the numbers are

(A) 8, 12

(B) 9, 12

(C) 10, 12

(D) 16, 14

Ans: B

Let the numbers be 3x and 4x.

Then, (4x)2 - (3x)2 = 63

⇒ 16x2 - 9x2 = 63

⇒ 7x2 = 63

⇒ x2 = 9 ⇒ x = 3.

∴ The numbers are 9 and 12.

Question: 4

Three numbers A, B and c are in the ratio of 12 : 15 : 25. If the sum of these numbers is 312, the ratio between the difference of B and A and the difference of C and B is

(A) 3 : 7

(B) 3 : 10

(C) 5 : 1

(D) 10 : 3

Ans: B

A : B : C = 12 : 15 : 25.

Let the number be 12x, 15x and 25x.

Required ratio = (B - A) : (C - B)

= (15x - 12x) : (25x - 15x) = 3x : 10x = 3 : 10.

Question: 5

In two types of powdered detergent the ratio of soda and soap dust is 2 : 19 and 1 : 11 respectively. If 7 kg of the first type is mixed with 4 kg of the second type, find the ratio of soda to soap dust in the new detergent mixture.

(A) 1 : 9

(B) 1 : 10

(C) 20 : 1

(D) 30 : 1

Ans: B

Quantity of soda in the mixture

= \$\$(7 × {2}/{21} + 4 × {1}/{12})\$\$kg = \$\$({2/3 } + {1/3})\$\$kg = 1 kg.

Quantity of soap dust in the mixture

= [(7 + 4) - 1]kg = 10 kg.

∴ Required ratio = 1 : 10.

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