1000+ Wipro Aptitude Questions and Answers Pdf - 1
Question: 1
Rs.2010 are to be divided among A, B, C in such a way that it A gets Rs.5, then B must get Rs.12 and if B gets Rs.4, then C must get Rs.550. The share of C will exceed that of B by
(A) Rs.240
(B) Rs.270
(C) Rs.420
(D) Rs.470
Ans: B
A : B = 5 : 12
B : C = 4 : 5.50 = $$12 : 16.5 = 12 : {33}/{2}$$
A : B : C = $$5 : 12 : {33}/{2}$$ = 10 : 24 : 33.
Sum of ratio terms = 10 + 24 + 33 = 67.
C’s share = Rs.$$(2010 × {33}/{67})$$ = Rs.990.
B’s share = Rs.$$(2010 × {24}/{67})$$ = Rs.720.
Required difference = Rs.(900 - 720) = Rs.270.
Question: 2
Rs.1050 are divided among P, Q and R. The share of P is $${2}/{5}$$ of the combined share of Q and R. P gets
(A) Rs.200
(B) Rs.220
(C) Rs.300
(D) Rs.320
Ans: C
P = $${2}/{5}(Q + R)$$ ⇒ P : (Q + R) = 2 : 5.
∴ P’s share = Rs.$$(1050 × {2}/{7})$$ = Rs.300.
Question: 3
Two numbers are in the ratio 3 : 4. If the difference of their squares is 63, then the numbers are
(A) 8, 12
(B) 9, 12
(C) 10, 12
(D) 16, 14
Ans: B
Let the numbers be 3x and 4x.
Then, (4x)2 - (3x)2 = 63
⇒ 16x2 - 9x2 = 63
⇒ 7x2 = 63
⇒ x2 = 9 ⇒ x = 3.
∴ The numbers are 9 and 12.
Question: 4
Three numbers A, B and c are in the ratio of 12 : 15 : 25. If the sum of these numbers is 312, the ratio between the difference of B and A and the difference of C and B is
(A) 3 : 7
(B) 3 : 10
(C) 5 : 1
(D) 10 : 3
Ans: B
A : B : C = 12 : 15 : 25.
Let the number be 12x, 15x and 25x.
Required ratio = (B - A) : (C - B)
= (15x - 12x) : (25x - 15x) = 3x : 10x = 3 : 10.
Question: 5
In two types of powdered detergent the ratio of soda and soap dust is 2 : 19 and 1 : 11 respectively. If 7 kg of the first type is mixed with 4 kg of the second type, find the ratio of soda to soap dust in the new detergent mixture.
(A) 1 : 9
(B) 1 : 10
(C) 20 : 1
(D) 30 : 1
Ans: B
Quantity of soda in the mixture
= $$(7 × {2}/{21} + 4 × {1}/{12})$$kg = $$({2/3 } + {1/3})$$kg = 1 kg.
Quantity of soap dust in the mixture
= [(7 + 4) - 1]kg = 10 kg.
∴ Required ratio = 1 : 10.
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