100+ Ratio and Proportion Questions with Solutions Pdf - 1
Question: 1
If A : B = 7 : 9 and B : C = 5 : 4, then A : B : C is
(A) 7 : 45 : 36
(B) 21 : 32 : 30
(C) 28 : 36 : 35
(D) 35 : 45 : 36
Ans: D
A : B = 7 : 9 and B : C = 5 : 4 = $$(5 × {9}/{5})$$ : $$(4 × {9}/{5})$$ = $$9 : {36}/{5}$$.
⇒ A : B : C = 7 : 9 : $${36}/{5}$$ = 35 : 45 : 36.
Question: 2
Of 132 examinees of a certain school, the ratio of successful to unsuccessful candidates is 9 : 2. If 4 more students passed, what would have been the ratio of successful to unsuccessful students?
(A) 3 : 28
(B) 4 : 25
(C) 25 : 4
(D) 28 : 5
Ans: D
Number of successful candidates = $$({9}/{11} × 132)$$ = 108.
Number of unsuccessful candidates = $$({2}/{11} × 132)$$ = 24.
∴ Required ratio = (108 + 4) : (24 - 4) = 112 : 20 = 28 : 5.
Question: 3
The sum of three numbers is 116. The second number and the third number are in the ratio of 9 : 16 while the first number and the third number are in the ratio of 1 : 4. Find the second number.
(A) 8
(B) 16
(C) 36
(D) 56
Ans: C
Second : Third = 9 : 16,
Third : First = 4 : 1 = 16 : 4.
∴ Second : Third : First = 9 : 16 : 4.
Second number = $$(116 × 9/29)$$ = 36.
Question: 4
A and B are two alloys of gold and copper prepared by mixing metals in the ratio 7 : 2 and 7 : 11 respectively. If equal quantities of the alloys are melted to form a third alloy C, then the ratio of gold and copper in alloy C will be
(A) 5 : 7
(B) 5 : 9
(C) 7 : 3
(D) 7 : 5
Ans: D
Gold in C = $$({7}/{9} + {7}/{18})$$ units = $${7}/{6}$$ units.
Copper in C = $$({2}/{9} + {11}/{18})$$ units = $${5}/{6}$$ units.
∴ Gold : Copper = $${7}/{6} : {5}/{6}$$ = 7 : 5.
Question: 5
Raj and Suraj bought a bottle of water together in which there was 2 litres of water. Raj drank 1/4th part of it. The rest water was drunk bu Suraj. Find the amount of water used by Suraj.
(A) 0.5 litres
(B) 1. 5 litres
(C) 2 litres
(D) 2.5 lites
Ans: B
Quantity of water in bottle = 2 litres
Part of water drank by Raj = $${1}/{4}$$ part
Part of water drank by Suraj = $${3}/{4}$$ part
Water taken by Suraj = $${3}/{4}$$ × 2 = 1.5 litres.
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