1000+ CIMB Aptitude Interview Questions and Answers Pdf - 1

Question: 1

A covered wooded box has the inner measures as 115 cm, 75 cm and 35 cm and the thickness of wood is 2.5 cm. Find the volume of the wood.

(A) 81000 cu.cm

(B) 81165 cu.cm

(C) 81775 cu.cm

(D) 82125 cu.cm

Ans: D

The external measures of the box are (115+ 5) cm, (75 + 5) cm and (35 + 5) cm i.e., 120 cm, 80 cm and 40 cm.

Volume of the wood = External volume - Internal volume

= [(120 × 80 × 40) - (115 × 75 × 35)] cm3

= (384000 - 301875) cm3 = 82125 cm3.

Question: 2

The cost of painting the whole surface area of a cube at the rate of 13 paisa per sq. cm is Rs.343.98. Then the volume of the cube is

(A) 8500 cm3

(B) 9000 cm3 >

(C) 9250 cm3

(D) 9261 cm3

Ans: D

Surface area = $$({34398}/{13})$$ = 2646 cm2

∴ 6a2 = 2646 ⇒ a2 = 441 ⇒ a = 21.

So, Volume = (21 × 21 × 21) cm3 = 9261 cm3.

Question: 3

If the numbers are representing volume and surface area of a cube are equal, then the length of the edge of the cube in terms of the unit of measurement will be

(A) 3

(B) 4

(C) 6

(D) 7

Ans: C

a3 = 6a2 ⇒ a = 6.

Question: 4

Shobhrak takes a cube of 1 m edge length and meticulously cubes, each of edge-length 1 mm from the parent cube. He joins these small cubes end to end. Thus, the total length of this cube robe will be

(A) 1 km

(B) 10 km

(C) 100 km

(D) 1000 km

Ans: D

Number of cubes formed = $${10^3 × 10^3 × 10^3} / {1 × 1 × 1}$$ = 10^9.

∴ Total length of cube robe = (1 × 109) mm = 109 mm

= $$({10^9} / {10^6})$$ km = 103 = 1000 km.

Question: 5

If three equal cubes are placed adjacently in a row, then the ratio of the total surface area of the new cuboid to the sum of the surface areas of the three cubes will be

(A) 1 : 3

(B) 5 : 9

(C) 7 : 9

(D) 9 : 1

Ans: C

Let the length of each edge of each cube be a.

Then, the cuboid formed by placing 3 cubes adjacently has the dimensions 3a, a and a.

Surfae area of the cuboid = 2[3a × a + a × a + 3a × a]

= 2[3a2 + a2 + 3a2] = 14a2.

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