1000+ CTBC Bank Interview Questions and Answers - 1

Ans: B

Ratio of the number of 50 paisa, 25 paisa and 10 paisa coins = 5 : 8 : 3.

Ratio of their values = $${5/2} : {8/4} : {3/10}$$

LCM of 2, 4 and 10 = 20

= $$({5}/{2} × 20)$$ : $$({8}/{4} × 20)$$ : $$({3}/{10} × 20)$$ = 50 : 40 : 6

Sum of the terms of ratio = 50 + 40 + 6 = 96

∴ Value of 50 paisa coins = $${50}/{96} × 144$$ = 75

∴ Number of 50 paisa coins = 75 × 2 = 150.

Ans: C

L.C.M. of 2, 3, 4, 5, 7 = 420.

Given ratio = $${1/2} : {1/3} : {1/4} : {1/5} : {1/7}$$

= $$({1}/{2} × 420) : ({1}/{3} × 420) : ({1}/{4} × 420) : ({1}/{5} × 420) : ({1}/{7} × 420)$$

= 210 : 140 : 105 : 84 : 60

∴ Required minimum amount = Sum of ratio terms

= Rs.(210 + 140 + 105 + 84 + 60) = Rs.599.

Ans: C

Let the values of one rupee, 50-paise and 25-pais coins be Rs. 2x, Rs. 3x and Rs.5x respectively.

Then, number of one rupee coins = 2x;

Number of 50-paise coins = $${3x}/{0.5}$$ = 6x;

Number of 25-paise coins = $${5x}/{0.25}$$ = 20x.

∴ 2x + 6x + 20x = 420

⇒ 28x = 420 ⇒ x = 15.

Hence, number of one rupee coins = 2 × 15 = 30.

Ans: C

Let the number of boys and girls, after leaving of 15 girls, be 2x and x respectively.

Then, $${2x – 45} / {x}$$ = $${1}/{5}$$

⇒ 10x – 225 = x

⇒ 9x = 225

⇒ x = 25.

∴ Original number of girls = x + 15 = (25 + 15) = 40.

Ans: D

Let C’s income be Rs.x.

Then, B’s income = 80% of Rs.x = Rs.$$({4x}/{5})$$.

A’s income = 110% of Rs.$$({4x}/{5})$$ = Rs.$$({110/100} ×{4x}/{5})$$ = Rs.$$({22x}/{25})$$.

∴ A : B : C = $${22x}/{25}$$ : $${4x}/{5}$$ : x = 22 : 20 : 25.