1000+ Goldman Sachs Aptitude Questions and Answers Pdf - 1

Ans; C

Area of the park = (60 × 40) m² = 2400 m²

Area of the lawn = 2109 m²

∴ Area of the crossroads = (2400 - 2109) m² = 291 m²

Let the width of the road be x metres. Then

60x + 40x – x² = 291

⇔ x² - 100x + 291 = 0 ⇔ (x = 97)

⇔ (x – 3) = 0 ⇔ x = 3.

Ans: C

Side of first square = $$({40}/{4})$$cm = 10 cm.

Side of second square = $$({32}/{4})$$cm = 8 cm.

Area of third square = [(10)² - (8)²]cm² = (100 - 64) cm² = 36 cm².

Side of third square = $$√36$$ cm = 6 cm.

∴ Required perimeter = (6 × 4) cm = 24 cm.

Ans: C

Distance to be covered in 1 min = $$({66 × 1000} / {60})$$m = 1100 m.

Circumference of the wheel = $$(2 × {22}/{7} × 0.70)$$m = 4.4 m.

∴ Number of revolutions per min. $$({1100} / {4.4})$$ = 250.

Ans: B

Ratio of sides = $${1/2} : {1/3} : {1/4}$$ = 6 : 4 : 3.

Perimeter = 52 cm. So, sides are

$$(52 × {6}/{13})$$cm, $$(52 × {4}/{13})$$ cm and $$(52 × {3}/{13})$$ cm.

So, a = 24 cm, b = 16 cm, c = 12 cm.

∴ Length of smallest side = 12 cm.

Ans: C

Let inner radius be r metres.

Then, 2Πr = 440 ⇒ r = $$(440 × {7}/{44})$$ = 70 m.

∴ Radius of outer circle = (70 + 14) m = 84 m.