# 100+ Problems on Area Questions for Bank Exams - 1

Question: 1

A housing society has been allotted a square piece of land measuring 2550.25 sq.m. What is the side of the plot?

(A) 50.5 m

(B) 50.25 m

(C) 50.65 m

(D) 50.85 m

Ans: A

Side = $$√ 2550.25$$ = $$√ {255025}/{100}$$ = $${505}/{10}$$ = 50.5 m.

Question: 2

The perimeter of a square and rectangle is the same. If the rectangle is 12 cm by 10 cm, then by what percentage is the area of the square more than that of the rectangle?

(A) $$1{1}/{6}$$

(B) $${5}/{6}$$

(C) 1

(D) $${2}/{3}$$

Ans: B

Perimeter of the square = Perimeter of the rectangle

= 2(12 + 10) cm = 44 cm.

Side of the square = $${44} /{4}$$ cm = 11 cm.

Area of the rectangle = (12 × 10) cm^{2} = 120 cm^{2}.

Area of the square = (11 × 11) cm^{2} = 121 cm^{2}.

∴ Required percentage = $$({1}/{120} × 100)$$% =$${5}/{6}$$%.

Question: 3

The length and breadth of the floor of the room are 20 feet and 10 feet respectively. Square tiles of 2 feet length of different colours are to be laid on the floor. Black tiles are laid in the first row on all sides. If white tiles are laid in the one third of the remaining and blue tiles in the rest, how many blue tiles will be there?

(A) 12

(B) 16

(C) 24

(D) 32

Ans: B

Area left after laying black tiles = [(20 - 4) × (10 - 4)] sq.ft = 96 sq.ft.

Area under white tiles = $$({1}/{3} × 96)$$sq.ft = 32 sq.ft.

Area under blue tiles = (96 – 32) sq.ft = 64 sq.ft.

Number of blue tiles = $${64} / {(2 × 2)}$$ = 16.

Question: 4

The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 7803 sq.metres, What is the breadth of the rectangular plot?

(A) 41 m

(B) 51 m

(C) 104 m

(D) 153 m

Ans: B

Let the breadth of the plot be x metres.

Then, length of the plot = (3x) metres.

x × 3x = 7803 ⇒ 3x^{2} = 7803 ⇒ x^{2} = 2601

⇒ x = $$√2601$$ = 51 m.

Question: 5

Find the area of a square, one of whose diagonals is 3.8 m long.

(A) 5.22 m^{2}

(B) 6.22 m^{2}

(C) 7.22 m^{2}

(D) 8.22 m^{2}

Ans: C

Area of the square = $${1}/{2}$$× (diagonal)^{2}
= $$({1}/{2} × 3.8 × 3.8)$$m^{2} = 7.22 m^{2}.

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