# 50+ Logical Reasoning Questions for Bank Exams Pdf - 1

Question: 1

A printer numbers the pages of a book starting with 1 and uses 3189 digits in all. How many pages does the book have?

(A) 1074

(B) 1075

(C) 1080

(D) 1094

Ans: A

No. of digits in 1 digit page nos. = 1 x 9 = 9.

No. of digits in 2 digit page nos. = 2 x 90 = 180.

No. of digits in 3 digit page nos. = 3 x 900 = 2700.

No. of digits in 4 digit page nos. = 3189 - (9 + 180 + 2700)

3189 - 2889 = 300.

No. of digits in 4 digit page nos. = 300 ÷ 4 = 75.

Hence, total number of pages = (999 + 75) = 1074.

Question: 2

A is 3 years younger than C but one year older than D. D is one year older than B but 4 years younger than C. C is 15 years old. What is the age of B in years?

(A) 9

(B) 10

(C) 11

(D) 12

Ans: B

We have : A = C - 3, A = D + 1, D = B + 1, D = C - 4, C = 15

Thus, D = C - 4 = 15 - 4 = 11

B = D - 1 = 11 - 1 = 10.

Question: 3

A man wears socks of two colours black and brown. He has altogether 20 black socks and 20 brown socks in a drawer. Supposing he has to take out the socks in the dark, how many must he take out to be sure that he has a matching pair?

(A) 1

(B) 2

(C) 3

(D) 4

Ans: C

Since there are socks of only two colours, so two out of any three socks must always be of the same colour.

Question: 4

A player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many diamonds as spades and twice as many hearts as diamonds. How many clubs does he told?

(A) 3

(B) 4

(C) 5

(D) 6

Ans: D

Clearly, the black cards are either clubs or spades while the red cards are either diamonds or hearts.

Let the number of spades be x. Then, number of clubs = (7 - x).

Number of diamonds = 2 x number of spades = 2x;

Number of hearts = 2 x number of diamonds = 4x.

Total number of cards = x + 2x + 4x + 7 - x = 6x + 7.

∴ 6x + 7 = 13 = 6x = 6

∴ x = 1.

Hence, number of clubs = (7 - x) = 6.

Question: 5

If you write down all the numbers from 1 to 100, then how many times do you write 3?

(A) 10

(B) 11

(C) 18

(D) 20

Ans: D

Clearly, from 1 to 100, there are ten numbers with 3 as the units digit 3, 13, 23, 33, 43, 53, 63, 73, 83, 93; and ten numbers with 3 as the ten's digit 30, 31, 32, 33, 34, 35, 36, 37, 38, 39.

So, required number = 10 + 10 = 20.

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