50+ Logical Reasoning Questions for Bank Exams Pdf - 2
Question: 6
A man has Rs. 480 in the denominations of one rupee notes, five rupee notes and ten rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has?
(A) 45
(B) 75
(C) 90
(D) 95
Ans: C
Let number of notes of each denomination be x.
Then, x + 5x + 10x = 480
⇒ 16 x = 480
⇒ x = 30.
Hence, total number of notes = 3x = 90.
Question: 7
A girl counted in the following way on the fingers of her hand : she started by calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5 and then reversed direction calling the ring finger 6, middle finger 7 and so on. She counted upto 1994. She ended counting on which finger?
(A) Middle finger
(B) Ring finger
(C) Index finger
(D) Thumb
Ans: C
Clearly, while counting, the numbers associated to the thumb will be 1, 9, 17, 25, i.e. numbers of the form (8n + 1). Since 1994 = 249 x 8 + 2, so 1993 shall correspond to the thumb and 1994 to the index finger.
Question: 8
After distributing the sweets equally among 25 children, 8 sweets remain. Had the number of children been 28, 22 sweets would have been left after equal distribution. What was the total number of sweets?
(A) 328
(B) 338
(C) 348
(D) 358
Ans: D
Let the total number of sweets be (25x + 8).
Then, (25x + 8) - 22 is divisible by 28
⇔ (25x - 14) is divisible by 28
⇔ 28x - (3x + 14) is divisible by 28
⇔ (3x + 14) is divisible by 28
⇔ x = 14.
∴ Total number of sweets = (25 x 14 + 18) = 358.Question: 9
A number consists of two digits whose sum is 11. If 27 is added to the number, then the digits change their places. What is the number?
(A) 37
(B) 47
(C) 65
(D) 83
Ans: B
Let the ten's digit be x. then, unit's digit = (11 - x).
So, number = 10x + (11 - x) = 9x + 11.
∴ (9x + 11) + 27 = 10 (11 - x) + x
∴ 9x + 38 = 110 - 9x
∴ 18x = 72
∴ x = 4.
Thus, ten's digit = 4 and unit's digit = 7.
Hence, required number = 47.
Question: 10
A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly?
(A) 12
(B) 14
(C) 16
(D) 18
Ans: C
Suppose the boy got x sums right and 2x sums wrong. Then, x + 2x = 48
⇒ 3x = 48
⇒ x= 16.
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