Time and Distance Questions for Bank PO, SO, Clerk Exams - 1
Question: 1
A boy goes to school with a speed of 3 km/hr and returns to the village with a speed of 2 km/hr. If he takes 5 hours in all, the distance between the village and the school is
(A) 5 km
(B) 6 km
(C) 7 km
(D) 8 km
Ans: B
Let the required distance be x km.
Then $${x}/{3} + {x}/{2}$$ = 5
⇒ 2x + 3x = 30 ⇒ 5x = 30
x = 6 km.
Question: 2
A man walked at a speed of 4 km/hr from point A to B and came back from point B to A at the speed of 6 km/hr. What would be the ratio of the time taken by the man in walking from point A to B to that from point B to A?
(A) 1 : 2
(B) 2 : 3
(C) 3 : 2
(D) 3 : 4
Ans: C
Ratio of speeds = 4 : 6 = 2 : 3.
∴ Ratio of times taken = $${1}/{2} : {1}/{3}$$ = 3 : 2.
Question: 3
Bombay Express left Delhi for Bombay at 14.30 hours, travelling at a speed of 60 km/hr and Rajdhani Express left Delhi for Bomaby on the same day at 16.30 hours travelling at a speed of 80 km/hr. How far away from Delhi will the two trains meet?
(A) 120 km
(B) 240 km
(C) 360 km
(D) 480 km
Ans: D
Let they meet x hours after 14.30 hours.
Then, 60x = 80(x - 2) ⇒ x = 8
∴ Required distance = (60 × 8) km = 480 km.
Question: 4
Akash leaves home for school which is 12 km from his house. After, the school, he goes to his club which is 7 km from his school. If his house, school and club all fall in a line, then what is the minimum distance he has to travel to get back home?
(A) 5 km
(B) 10 km
(C) 15 km
(D) 17 km
Ans: A
For the distance to be minimum, the club must lie between Akash’s home and school.
Hence, required distance = (12 – 7) km = 5 km.
Question: 5
A man travelled from the village to the post office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post office from the village.
(A) 10 km
(B) 20 km
(C) 30 km
(D) 40 km
Ans: B
Average speed = $$({2xy}/ {x + y})$$ km/hr = $$({2 × 25 × 4} / {25 + 4})$$ km/hr = $${200}/{29}$$ km/hr.
Distance travelled in 5 hours 48 minutes,
i.e. $$5{4}/{5}$$ hrs = $$({200/29} ×{ 29/5})$$ km = 40 km.
∴ Distance of the post office from the village = $$({40}/{2})$$ = 20 km.
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