1000+ JP Morgan Aptitude Test Questions and Answers Pdf - 1

Question: 1

The sum of two numbers is 40 and their product is 375. What will be the sum of their reciprocals?

(A) $${1}/{40}$$

(B) $${1}/{80}$$

(C) $${8}/{75}$$

(D) $${75}/{4}$$

Ans: C

Let t he numbers be x and y.

Then, x + y = 40 and xy = 375.

∴ $${1/x} + {1/y}$$

= $${x + y}/{xy}$$

= $${40} /{375}$$

= $${8}/{75}$$.

Question: 2

In a two digit number, the digit in the unit’s place is four times the digit in ten’s place and sum of the digits is equal to 10. What is the number?

(A) 14

(B) 28

(C) 41

(D) 64

Ans: B

Let the ten’s digit be x.

Then, unit’s digit = 4x.

∴ x + 4x = 10

⇔ 5x = 10

⇔ x = 2.

So, ten’s digit = 2, unit’s digit = 8.

Hence, the required number is 28.

Question: 3

A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by

(A) 3

(B) 7

(C) 11

(D) 13

Ans: C

Let the ten’s digit be x and unit’s digit be y.

Then, number = 10x + y.

Number obtained by interchanging the digits = 10y + x.

∴ (10x + y) + (10y + x)

= 11(x + y), which is divisible by 11.

Question: 4

A number consists of 3 digits whose sum is 10. The middle digit is equal to the sum of the other two and the number will be increased by 99 if its digits are reversed. The number is

(A) 143

(B) 232

(C) 253

(D) 262

Ans: C

Let the middle digit be x.

Then, 2x = 10 or x = 5.

So, the number is either 253 or 352.

Since, the number increases on reversing the digits. So the hundred’s digit is smaller than the unit’s digit. Hence, required number = 253.

Question: 5

If a number is decreased by 4 and divided by 6, the result is 8. What would be the result if 2 is subtracted from the number and then it is divided by 5?

(A) 10

(B) 11

(C) 13

(D) 14

Ans: A

Let the number be x.

Then, $${x - 4}/{6}$$ = 8

⇔ x - 4 = 48

⇔ x = 52.

∴ $${x - 2} / {5}$$ = $${52 - 2} /{5}$$ = $${50}/{5}$$ = 10.

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