1000+ Numerical Aptitude Questions and Answers Pdf - 1
Question: 1
A hemispherical bowl of internal radius 12 cm contains liquid. This liquid is to be filled into cylindrical container of diameter 4 cm and height 3 cm. The number of containers that is necessary to empty the bowl is
(A) 80
(B) 86
(C) 96
(D) 106
Ans: C
Volume of hemispherical bowl = $$({2/3} × Π × 12 × 12 × 12)$$ cm3.
Volume of 1 cylindrical container = (Π × 2 × 2 × 3) cm3
∴ Number of containers required = $${2}/{3}$$ × $${12 × 12 × 12} / {2 × 2 × 3}$$ = 96.
Question: 2
The base of a right prism is a trapezium whose lengths of two parallels sides are 10 cm and 6 cm and distance between them is 5 cm. If the heights of the pris2m is 8 cm, its volume is
(A) 300 cm3
(B) 310 cm3
(C) 320 cm3
(D) 340 cm3
Ans: C
Length of parallel side of prism = 10 cm and 6 cm
Height of prism = 8 cm
∴ Volume of prism = $${1}/{2}(10 + 6) × 5 × 8$$
=$${1}/{2}× 16 × 5 × 8$$ = 320 cm3.
Question: 3
Except for one face of a given cube, identical cubes are glued through their faces to all the other faces of the given cube. If each side of the given cube measures 3 cm, then what is the total surface area of the solid body thus formed?
(A) 225 cm2
(B) 234 cm2
(C) 244 cm2
(D) 274 cm2
Ans: B
Clearly, each of the 5 faces of the given cube are glued to a face of another cube.
∴ Total surface area of the solid 5 × 5a2 + a2 = 26a2
= (26 × 32)cm2 = 234 cm2.
Question: 4
An open box is made of wood 3 cm thick. Its external dimensions are 1.46 m, 1.16 m and 8.3 dm. The cost of painting the inner surface of the box at 50 paise per 100 sq. cm is
(A) 177
(B) 187
(C) 277
(D) 377
Ans: C
Internal length = (146 - 6) cm = 140 cm.
Internal breadth = (116 - 6) cm = 110 cm.
Internal depth = (83 - 3) cm = 80 cm.
Area of inner surface = [2(l + b) × h] + lb
= [2 (140 + 110) × 80 + 140 × 110]cm2 = 55400 cm2.
∴ Cost of painting = Rs.$$({1/2}× {1/100} × 55400)$$ = Rs.277.
Question: 5
The radius of a hemispherical bowls is 6 cm. The capacity of the bowl is
(A) 345.53 cm3
(B) 422 cm3
(C) 452.57 cm3
(D) 495.51 cm3
Ans: C
Radius of hemisphere bowl = 6 cm
∴ Volume of hemisphere = $${2}/{3}$$ Π r3
= $${2/3} × {22/7}$$ × 6 × 6 × 6
= $${9504}/{21}$$ = 452.57 cm3
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