# 1000+ Numerical Aptitude Questions and Answers Pdf - 1

Question: 1

A hemispherical bowl of internal radius 12 cm contains liquid. This liquid is to be filled into cylindrical container of diameter 4 cm and height 3 cm. The number of containers that is necessary to empty the bowl is

(A) 80

(B) 86

(C) 96

(D) 106

Ans: C

Volume of hemispherical bowl = \$\$({2/3} × Π × 12 × 12 × 12)\$\$ cm3.

Volume of 1 cylindrical container = (Π × 2 × 2 × 3) cm3

∴ Number of containers required = \$\${2}/{3}\$\$ × \$\${12 × 12 × 12} / {2 × 2 × 3}\$\$ = 96.

Question: 2

The base of a right prism is a trapezium whose lengths of two parallels sides are 10 cm and 6 cm and distance between them is 5 cm. If the heights of the pris2m is 8 cm, its volume is

(A) 300 cm3

(B) 310 cm3

(C) 320 cm3

(D) 340 cm3

Ans: C

Length of parallel side of prism = 10 cm and 6 cm

Height of prism = 8 cm

∴ Volume of prism = \$\${1}/{2}(10 + 6) × 5 × 8\$\$

=\$\${1}/{2}× 16 × 5 × 8\$\$ = 320 cm3.

Question: 3

Except for one face of a given cube, identical cubes are glued through their faces to all the other faces of the given cube. If each side of the given cube measures 3 cm, then what is the total surface area of the solid body thus formed?

(A) 225 cm2

(B) 234 cm2

(C) 244 cm2

(D) 274 cm2

Ans: B

Clearly, each of the 5 faces of the given cube are glued to a face of another cube.

∴ Total surface area of the solid 5 × 5a2 + a2 = 26a2

= (26 × 32)cm2 = 234 cm2.

Question: 4

An open box is made of wood 3 cm thick. Its external dimensions are 1.46 m, 1.16 m and 8.3 dm. The cost of painting the inner surface of the box at 50 paise per 100 sq. cm is

(A) 177

(B) 187

(C) 277

(D) 377

Ans: C

Internal length = (146 - 6) cm = 140 cm.

Internal breadth = (116 - 6) cm = 110 cm.

Internal depth = (83 - 3) cm = 80 cm.

Area of inner surface = [2(l + b) × h] + lb

= [2 (140 + 110) × 80 + 140 × 110]cm2 = 55400 cm2.

∴ Cost of painting = Rs.\$\$({1/2}× {1/100} × 55400)\$\$ = Rs.277.

Question: 5

The radius of a hemispherical bowls is 6 cm. The capacity of the bowl is

(A) 345.53 cm3

(B) 422 cm3

(C) 452.57 cm3

(D) 495.51 cm3

Ans: C

Radius of hemisphere bowl = 6 cm

∴ Volume of hemisphere = \$\${2}/{3}\$\$ Π r3

= \$\${2/3} × {22/7}\$\$ × 6 × 6 × 6

= \$\${9504}/{21}\$\$ = 452.57 cm3

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