# 100+ Ratio and Proportion Questions for Bank Exams - 1

Question: 1

A person spends Rs. 8100 in buying some tables at Rs. 1200 each and some chairs at Rs. 300 each. The ratio of the number of chairs to that of tables when the maximum possible number of tables is purchased, is

(A) 1 : 1

(B) 1 : 2

(C) 2 : 1

(D) 5 : 7

Ans: B

Maximum possible number of tables = 6.

[∴ 1200 × 6 = 7200].

Number of chairs purchased = \$\${8100 – 7200} / {300}\$\$ = \$\${900} / {300}\$\$ = 3.

Hence, required ratio = 3 : 6 = 1 : 2.

Question: 2

Two numbers are in the ratio 4 : 5 and their L.C.M. is 180. The smaller number is

(A) 9

(B) 15

(C) 36

(D) 45

Ans: C

Let the numbers be 4x and 5x.

Then, their L.C.M. = 20x .

20x = 180 or x = 9.

∴ Smaller number = 4x = 4 × 9 = 36.

Question: 3

In two types of powdered detergent the ratio of soda and soap dust is 2 : 19 and 1 : 11 respectively, if 7 kg of the first type is mixed with 4 kg of the second type, find the ratio of soda to soap dust in the new detergent mixture.

(A) 1 : 9

(B) 1 : 10

(C) 9 : 1

(D) 20 : 1

Ans: B

Quantity of soda in the mixture

= \$\$(7 × {2}/{21} + 4 × {1}/{12})\$\$ kg = \$\$({2}/{3} + {1}/{3})\$\$kg = 1 kg.

Quantity of soap dust in the mixture

= [(7 + 4) - 1] kg = 10 kg.

∴ Required ratio = 1 : 10.

Question: 4

Smita works in her office for 6 hours and Kajal works in her office for 7 hours 30 minutes. Find the ratio of their working hours.

(A) 3 : 5

(B) 4 : 2

(C) 4: 5

(D) 6 : 7

Ans: C

Working hours of Smita = 6 hours

Working hours of Kajal = 7 hours 30 minutes = \$\$1{1}/{2}\$\$hours

Required ratio = \$\$6 : 7{1}/{2}\$\$ = \$\$6: {15}/{2}\$\$

= 12 : 15 = 4 : 5.

Question: 5

If \$\${1}/{x} : {1}/{y} : {1}/{z}\$\$ = 2 : 3 : 5, then x : y : z is equal to

(A) 2 : 3 : 5

(B) 5 : 3 : 2

(C) 6: 10 : 15

(D) 15 :10 : 6

Ans: D

\$\${1}/{x} : {1}/{y} : {1}/{z}\$\$ = 2 : 3 : 5 ⇒ x : y : z = \$\${1}/{2} : {1}/{3} : {1}/{5}\$\$ = 15 : 10 : 6.

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