100+ Percentage Questions and Answers Pdf - 1

Ans: C

38% of 341 = $$({38} / {100} × 341)$$ = $${12958}/{100}$$ = 129.58.

Ans: A

Required percentage = $$({5} / {2250} × 100)%$$ = $${2} / {9}%$$.

Ans: D

Clearly, 60% of 28% of 240 = $$({60} / {100} × {28}/{100} × 240)$$

                                           = $$({30}/{100} × {28}/{100} × 2 × 240)$$

                                           = $$({30}/{100} × {28}/{100} × 480)$$

                                           = 30% of 28% of 480.

Ans: C

Total number of students = 1100 + 700 = 1800.

Number of students passed = (42% of 1100 + 30% of 700)

= (462 + 210) = 672.

Number of failures = 1800 – 672 = 1128.

∴ Percentage failure = $$({1128} / {1800} × 100)$$% = $$62{2}/{3}$$%.

Ans: B

Let original consumption = 100 kg and new consumption = x kg.

So, 100 × 16 = x × 20 ⇔ x = 80.

∴ Reduction in consumption = 20%.