100+ Square Root and Cube Root Questions for Bank Exams - 1
Question: 1
The least perfect square number divisible by 3, 4, 5, 6 and 8 is
(A) 1200
(B) 2400
(C) 3600
(D) 4800
Ans: C
L.C.M. of 3, 4, 5, 6, 8 is 120. Now, 120 = 2 × 2 × 2 × 3 × 5.
To make it a perfect square, it must be multiplied by 2 × 3 × 5.
So, required number = 22 × 22 × 32 × 52 = 3600.
Question: 2
1.52 × $$√0.0225$$ = ?
(A) 0.3375
(B) 0.0375
(C) 3.275
(D) 32.75
Ans: A
1.52 × $$√0.0225$$ = 1.52 × $$√{225/10000}$$ = $$2.25 × {15}/{100}$$
= 2.25 × 0.15 = 0.3375.
Question: 3
The number of digits in the square root of 625685746009 is
(A) 3
(B) 4
(C) 5
(D) 6
Ans: D
The number of digits in the square root of a perfect square number of n digits is
i. $${n}/{2}$$, if n is even
ii. $${n+1} / {2}$$, if n is odd
iii. Here, n = 12. So required number of digits = $${n}/{2}$$ = $${12}/{2}$$ = 6.
Question: 4
($$√{225/729}$$ - $$√{25/144}$$) ÷ $$√{16/81}$$ = ?
(A) $${1}/{48}$$
(B) $${5}/{16}$$
(C) $${5}/{48}$$
(D) $${6}/{18}$$
Ans: B
Given expression = ($$√225 / √729$$ - $$√25/√144$$) ÷ $$√16 / √81$$
= $$({15}/{27} – {5}/{12})$$ ÷ $${4}/{9}$$ = $$({15}/{108} × {9}/{4})$$ = $${5}/{16}$$.
Question: 5
If $$√3^n$$ = 729, then the value of n is
(A) 6
(B) 8
(C) 10
(D) 12
Ans: D
$$√3^n$$ = 729 = 36 ⇔ ($$√3^n$$)2 = (36)2 ⇔ $$3^n$$ = 312 ⇔ n = 12.
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