1000+ Standard Chartered Bank Aptitude Questions and Answers Pdf - 1

Ans: C

986 × 137 + 986 × 863 = 986 × (137 + 863) = 986 × 1000 = 986000.

Ans: C

Let the required product be n (n +1 ) (n + 2). Then

n = 1 ⇒ n (n + 1) (n + 2) = (1 × 2 × 3) = 6.

n = 2 ⇒ n (n + 1) (n + 2) = (2 × 3 × 4) = 24.

n = 3 ⇒ n (n + 1) (n + 2) = (3 × 4 × 5) = 60.

So, each support product is divisible by 6.

Ans: C

(1³ - 1) = 0, (2³ - 2) = 6, (3³ - 3) = 24, (4³ - 4) = 60 and

So on, each one of which is divisible by 6.

Ans: C

$$({1}/{5})$$²⁰⁰⁰ = (0.2)²⁰⁰⁰

Last digit of (0.2)²⁰⁰⁰ = Last digit of (0.2)⁴ = 6.

Ans: B

(2¹² - 1) = (4096 -1) = 4095, which is clearly divisible by 3, 5, 7 and 13 i.e, four numbers in all.