100+ Problems on Trains Questions for Bank Exams - 1
Question: 1
A train, 150 m long takes 30 seconds to cross a bridge 500 m long. How much time will the train take to cross a platform 370 m long?
(A) 18 sec
(B) 21 sec
(C) 24 sec
(D) 30 sec
Ans: C
Speed of the train = $$({150 + 500} / {30})$$ m/sec = $$({65} / {3})$$ m/sec.
∴ Required time = $$[{150 + 370} / {65/3}]$$ sec = $$(520 × {3}/{65})$$ sec = 24 sec.
Question: 2
Two trains of lengths 120 m and 90 m are running with speeds of 80 km/hr and 55 km/hr respectively towards each other on parallel lines. If they are 90 m apart, after how many seconds they will cross each other?
(A) 5.6 sec
(B) 7.2 sec.
(C) 7.7 sec.
(D) 8 sec.
Ans: D
Relative speed = (80 + 55) km/hr = 135 km/hr
= $$(135 × {5}/{18})$$ m/sec = $$({75}/{2})$$ m/sec.
Distance covered = (120 + 90 + 90) m = 300 m.
Required time = $$(300 × {2}/{75})$$ sec = 8 sec.
Question: 3
Two trains 250 m and 200 m long are running on parallel track at the rate of 36 km/hr and 45 km/hr respectively. In how much time will they cross each other, if they are running in the same direction?
(A) 72 sec
(B) 144 sec
(C) 160 sec
(D) 180 sec
Ans: D
Relative speed of faster train w.r.t slower train
= 45 - 36 = 9 km/hr = $$9 × {5}/{18}$$ m/s = 2.5 m/s
Time taken to cross each other = $${Sum of lengths of train} / {Relative speed of train}$$
Time taken to cross each other = $${250 + 200} / {2.5}$$ = $${450} / {2.5}$$ = 180 sec.
Question: 4
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
(A) 5 sec
(B) 6 sec
(C) 7 sec
(D) 8 sec
Ans: B
Speed of the train relative to man = (60 + 6) km/hr
= 66 km/hr = $$(66 × {5}/{18})$$ m/sec. = $$({55}/{3})$$m/sec.
∴ Time taken to pass the man = = $$(110 × {3}/{55})$$ sec = 6 sec.
Question: 5
A 150 m long train is running with a speed of 68 kmph. In what time will it pass a man who is running at 8 kmph in the same direction in which the train is going?
(A) 7 sec
(B) 9 sec
(C) 10 sec
(D) 13 sec
Ans: B
Speed of the train relative to man = (68 – 8) kmph
= $$(60 × {5}/{18})$$m/sec = $$({50}/{3})$$m/sec.
Time taken by the train to cross the man
= Time taken by it cover 150 m at $$({50}/{3})$$m/sec = $$(150 × {3}/{50})$$sec = 9 sec.
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