100+ Problems on Trains Questions for IBPS, SBI PO, SO, Clerk - 1

Ans: B

Speed = $$(60 × {5}/{18})$$ m/sec = $${50}/{3}$$ m/sec.

Total distance covered = (100 + 140) m = 240 m.

∴ Required time = $$(240 × {3}/{50})$$ sec = $${72}/{5}$$ sec = 14.4 sec.

Ans: C

Speed of the train = $$(30 × {5}/{18})$$m/sec = $$({25}/{3})$$m/sec.

Distance moved in passing the standing man = 100 m.

Required time taken = $$100 /({25/3})$$ = $$(100 × {3}/{25})$$ sec = 12 sec.

Ans: D

Let the length of the train be x metres.

Then, length of the platform = (2x) metres.

Speed of the train = $$(90 × {5}/{18})$$ m/sec = 25 m/sec.

∴ $${x + 2x} /{25}$$ = 36 ⇔ 3x = 900 ⇔ x = 300.

Hence, length of platform = 2x = (2 × 300) m = 600 m.

Ans: C

Speed = $$(90 × {5}/{18})$$ m/sec = 25 m/sec.

Total distance covered = (120 + 230) m = 350 m.

∴ Required time = $$({350} / {25})$$sec = 14 sec.

Ans: B

Distance covered in passing the platform = (160 + 160) m = 320 m.

∴ Speed of train = $$({320}/{16})$$m/sec

= 20 m/sec = $$(20× {18}/{5})$$km/hr = 72 km/hr.