# TNPSC Number System Aptitude Questions and Answers - 1

Question: 1

7386038 is divisible by

(A) 11

(B) 9

(C) 4

(D) 3

Ans: A

Given number is 7386038.

Sum of its digits = 35, which is not divisible by any of 3 and 9.

So, the given number is not divisible by any 3 and 9.

Also, 38 is not divisible by 4.

So, the given number is not divisible by 4.

Question: 2

Which of the following numbers should be added to 8567 to make it exactly divisible by 4?

(A) 3

(B) 4

(C) 5

(D) None of these

Ans: D

On dividing 8567 by 4, the remainder is 3.

To make it divisible by 4, we must add 1 to it.

Question: 3

How many numbers less than 1000 are multiple of both 10 and 13?

(A) 6

(B) 7

(C) 8

(D) 9

Ans: B

Required numbers are multiples of (10 × 13), i.e., 130.

These numbers are 130, 260, 390, 520, 650, 780 and 910.

They are 7 in number.

Question: 4

A number when divided by the sum of 555 and 445 gives two times their difference as quotient and 30 as the remainder. The number is

(A) 1220

(B) 1250

(C) 22030

(D) 220030

Ans: D

Divisor = (555 + 445) = 1000, Quotient = 2(555 – 445) = 2× 110 = 220 and Remainder = 30.

∴ Required number = (1000 × 220) + 30 = 220000 + 30 = 220030.

Question: 5

How many numbers will be there between 300 and 500, where 4 comes only one time?

(A) 89

(B) 99

(C) 110

(D) 120

Ans: B

From 300 to 399, we note that when ‘4’ comes only one time = 19 such instances.

From 400 to 499, we note that when ‘4’ comes only one time = 80 such instances.

So, total = (19 + 80) = 99 such instances.

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