Aptitude Percentage TNPSC Previous Year Questions - 1

Ans: C

Quantity of pulp in 100 kg of fresh fruits = (100 - 68)% of 100 kg = 32 kg.

Let the quantity of dry fruit obtained be x kg.

Then, (100 – 20)% of x = 32.

⇔ $${80}/{100}$$x = 32

⇔ x = $$({32 × 100} / {80})$$ = 40.

Ans: C

Given 32% of 825 + 25% of 1440 = 1025 – (?)

(?) = [1025 – (32% of 825) – (25% of 1440)]

⇒ 1025 – $$({32 × 825} / {100})$$ – $$({25 × 1440}/{100})$$

= (1025 - 264 - 360)

= 401.

Ans: B

Let total votes in village = 100

Losing candidate got votes = 30% of 100 = 30 votes

Winner’s and nearer rival’s votes

= $$100 - {30}/{100} × 100$$ = 70

∴ If both get equal votes then, it should be 35.

∴ Minimum difference between winner and nearer rival = (36 - 34) = 2.

Ans: A

Let the total production be x lakh tons.

Then, 15% of x – 10% of x = (40 – 30) lakh tons

⇔ 5% of x = 10 lakh tons

⇔ x = $$({10 × 100} / {5})$$ = 200 lakh tons.

Ans: C

Let 40% of 265 + 35% of 180 = 50% of x.

Then, $$({40}/{100} × 265)$$ + $$({35}/{100} × 180)$$ = $$({50}/{100} × x)$$

⇒ 106 + 63 = $${x}/{2}$$

⇒ x = 169 × 2 = 338.