1000+ Time and Distance Online Test - 1

Question: 1

A flight of Jet Airways from Delhi to Mumbai has an average speed of 700 km/hr without any stoppage, whereas a flight of Kingfisher from Delhi to Mumbai has an average speed of 560 km/hr with stoppage at Baroda. What is the average stoppage time per hour of kingfisher flight if both the planes fly at the same speed?

(A) 8 min

(B) 12 min

(D) 24 min

View Answer

Ans: B

Due to stoppage, Kingfisher flight covers (700 - 560) = 140 km less per hour.

Time taken to cover 140 km = $$({140}/{700} × 60)$$min = 12 min.

Hence, stoppage time per hour = 12 min.

Question: 2

The ratio of the speeds of a car, a train and a bus is 5 : 9 : 4. The average speed of the car, the bus and the train is 72 km/hr/ What is the average speed of the car and the train together?

(A) 78 km/hr

(B) 80 km/hr

(D) 84 km/hr

View Answer

Ans: D

Let the speeds of the car, train and bus be 5x, 9x and 4x km/hr respectively.

Then, $${5x + 9x + 4x} / {3}$$ = 72 ⇒ 6x = 72 = x = 12.

∴ Speed of the car = 60 km/hr.

Speed of the train = 108 km/hr.

Average speed of car and train = $$({60 + 108}{2})km/hr$$ = 84 km/hr.

Question: 3

The speed of a railway engine is 42 km/hr when no compartment is attached and the reduction in speed is directly proportional to the square root of the number of compartments attached. If the speed of the train carried by this engine is 24 km/hr with 9 compartments attached, the maximum number of compartments that the engine can pull is

(A) 35

(B) 42

(D) 48

View Answer

Ans: D

On attaching 9 compartments to the engine, we have reduction in speed = k $$√ 9$$ = 3 k where k is a constant.

∴ 42 – 3k = 24 or 3k = 18 or k = 6.

For the speed of the engine to be zero, let the number of compartments attached be x.

Then, 42 - 6 $$√ x$$ = 0 ⇒ 6 $$√ x$$ = 42 ⇒ $$√ x$$ = 7 ⇒ x = 49.

Hence, maximum number of compartments

that the engine can pull = (49 - 1) = 48.

Question: 4

Two boys A and B start at the same time to ride from Delhi to Meerut, 60 km away. A travels 4 km an hour slower than B, B reaches Meerut and at once turns back meeting A, 12 km from Meerut. A’s rate was

(A) 4 km/hr

(B) 8 km/hr

(D) 16 km/hr

View Answer

Ans: B

Let A’s speed = x km/hr.

Then, B’s speed = (x + 4) km/hr.

Clearly, time taken by B to cover (60 + 12) i.e., 72 km

= time taken by A to cover (60 - 12) i.e. 48 km.

∴ $${72}/{x + 4}$$ = $${48}/{x}$$ ⇒ 72x = 48x + 192 ⇒ 24x = 192 ⇒ x = 8.

Hence A’s speed = 8 km/hr.

Question: 5

A distance of 425 km separates two trains moving towards each other at a speed of 200 km/hr each. What will be the distance between them after 1 hr 30 min, if they reduce their speed by half, every half an hour?

(A) 60 km

(B) 75 km

(D) 140 km

View Answer

Ans; B

Relative speed = (200 + 200) km/hr = 400 km/hr.

Distance covered in 1 hr 30 min

= (400 × $${1}/{2}$$+ 200 × $${1}/{2}$$ + 100 × $${1}/{2}$$)km

= (200 + 100 + 50) km = 350 km.

Hence distance between the trains = (425 - 350) km = 75 km.

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1000+ Time and Distance Online Test - 1

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