100+ Problems on Ages TNPSC Questions - 1

Question: 1

Ratio of Rani’s and Komal’s ages is 3 : 5 respectively. Ratio of Komal’s and Pooja’s ages is 2 : 3 respectively. If Rani is two fifth of Pooja’s age, what is Rani’s age?

(A) 10 years

(B) 14 years

(C) 15 years

(D) Cannot be determined

Ans: D

Rani’s age : Komal’s age = 3 : 5 = $$ {3}/{5} : 1$$.

Komal’s age : Pooja’s age = 2 : 3 = $$1 : {3}/{2}$$.

Rani’s age : Komal’s age : Pooja’s ages = $${3}/{5} : 1: {3}/{2}$$ = 6 : 10 : 15.

Let Rani’s age be x years. Then, Komal’s age = 10x years and Pooja’s age = 15x years.

Rani’s age = $${2}/{5}$$ of Pooja’s age ⇒ 6x = $${2}/{5}$$ × 15x.

Thus, we cannot find the value of x and therefore of 6x.

So, the answer cannot be determined.

Question: 2

A man is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Rohit’s age?

(A) 2 times

(B) $$2{1}/{2}$$

(C) 3 times

(D) 4 times

Ans: A

Let Ronit’s present age be x years.

Then, the man’s age = (x + 3x) years = 4x years.

4x + 8 = $${5}/{2}$$(x + 8) ⇒ 8x + 16 = 5x + 40 ⇒ 3x = 24 ⇒ x = 8.

∴ Required ratio = $${(4x + 16)}/{(x + 16)}$$ = $${(4 × 8 + 16)} /{(8 + 16)}$$ = $${48}/{24}$$ = 2 times.

Question: 3

The ratio of the present ages of a mother and her daughter is 7 : 1. Four years ago, the ratio of their ages was 19 : 1. What will be the mother’s age four years from now?

(A) 36 years

(B) 38 years

(C) 42 years

(D) 46 years

Ans: D

Let mother’s age be 7x years.

Then, daughter’s age = x years. = $${7x - 4}/{x - 4}$$ = $${19}/{1}$$

⇒ 7x - 4 = 19 (x - 4)

⇒ 19x - 7x = 76 - 4

⇒ 12x = 72

⇒ x = 6.

Mother’s age after 4 years = (7x + 4)

= (7 × 6 + 4) years = 46 years.

Question: 4

The age of the mother today is thrice that of her daughter. After 12 years, the age of the mother will be twice that of her daughter. The age of the daughter today is

(A) 10 years

(B) 12 years

(C) 14 years

(D) 16 years

Ans: B

Let daughter’s age be x years.

Then, mother’s age = 3x years.

⇒ (3x + 12) = 2(x + 12)

⇒ 3x + 12 = 2x + 24 ⇒ x = 12.

∴ Daughter’s age today = 12 years.

Question: 5

The present ages of three persons are in the proportion 4 : 7 : 9. Eight years ago, the sum of their ages was 56 years. The present age of the eldest person is

(A) 28 years

(B) 32 years

(C) 36 years

(D) 46 years

Ans: C

A : B : C = 4 : 7 : 9 and (A + B + C) = 56 + (8 + 8 + 8) = 80.

∴ C’s age = $$(80 × {9}/{20})$$ years = 36 years.

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