100+ Problems on Ages TNPSC Questions - 1

Ans: D

Rani’s age : Komal’s age = 3 : 5 = $$ {3}/{5} : 1$$.

Komal’s age : Pooja’s age = 2 : 3 = $$1 : {3}/{2}$$.

Rani’s age : Komal’s age : Pooja’s ages = $${3}/{5} : 1: {3}/{2}$$ = 6 : 10 : 15.

Let Rani’s age be x years. Then, Komal’s age = 10x years and Pooja’s age = 15x years.

Rani’s age = $${2}/{5}$$ of Pooja’s age ⇒ 6x = $${2}/{5}$$ × 15x.

Thus, we cannot find the value of x and therefore of 6x.

So, the answer cannot be determined.

Ans: A

Let Ronit’s present age be x years.

Then, the man’s age = (x + 3x) years = 4x years.

4x + 8 = $${5}/{2}$$(x + 8) ⇒ 8x + 16 = 5x + 40 ⇒ 3x = 24 ⇒ x = 8.

∴ Required ratio = $${(4x + 16)}/{(x + 16)}$$ = $${(4 × 8 + 16)} /{(8 + 16)}$$ = $${48}/{24}$$ = 2 times.

Ans: D

Let mother’s age be 7x years.

Then, daughter’s age = x years. = $${7x - 4}/{x - 4}$$ = $${19}/{1}$$

⇒ 7x - 4 = 19 (x - 4)

⇒ 19x - 7x = 76 - 4

⇒ 12x = 72

⇒ x = 6.

Mother’s age after 4 years = (7x + 4)

= (7 × 6 + 4) years = 46 years.

Ans: B

Let daughter’s age be x years.

Then, mother’s age = 3x years.

⇒ (3x + 12) = 2(x + 12)

⇒ 3x + 12 = 2x + 24 ⇒ x = 12.

∴ Daughter’s age today = 12 years.

Ans: C

A : B : C = 4 : 7 : 9 and (A + B + C) = 56 + (8 + 8 + 8) = 80.

∴ C’s age = $$(80 × {9}/{20})$$ years = 36 years.