1000+ TNPSC Aptitude Study Material in English Pdf - 1

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tnpsc model questions - Online Test

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Question: 1

Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is

(A) 36

(B) 44

(D) 48

View Answer

Ans: D

Relative speed = (60 + 90) km/hr

= $$(150 × {5}/{18})$$ m/sec = $$({125}/{3})$$m/sec.

Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

Required time = $$(2000 × {3}/{125})$$ sec = 48 sec.

Question: 2

A train is moving at a speed of 132 km/hr. If the length of the train is 110 m, how long will it take to cross a railway platform 165 m long?

(A) $$7{1}/{2}$$ sec

(B) $$8{1}/{2}$$ sec

(D) $$9{2}/{3}$$ sec

View Answer

Ans: A

Speed of train = $$(132 × {5}/{18})$$ m/sec = $$({110} / {3})$$ m/sec.

Distance covered in passing the platform = (110 + 165) m = 275 m.

∴ Time taken = $$(275 × {3}/{110})$$ sec = $${15}/{2}$$ sec = $$7{1}/{2}$$ sec.

Question: 3

In what time will a train 100 metres long cross an electric pole, if its speed be 144 km/hr?

(A) 22.5 seconds

(B) 2.5 seconds

(D) 12.5 seconds

View Answer

Ans: B

Speed = $$(144 × {5}/{18})$$m/sec = 40 m/sec.

Time taken = $$({100} / {40})$$ sec = 2.5 sec.

Question: 4

A train running at the speed of 60 kmph crosses a 200 m long platform in 27 seconds. What is the length of the train?

(A) 200 metres

(B) 250 metres

(D) 290 metres

View Answer

Ans: B

Speed = $$(60 × {5}/{18})$$m/sec = $$({50}/{3})$$ m/sec.

Time = 27 sec.

Let the length of the train be x metres.

Then, $${x + 200} / {27}$$ = $${50}/{3}$$ ⇔ x + 200 = $$({50}/{3} × 27)$$ = 450

⇔ x = 250.

Question: 5

Two stations A and B are 110 km apart on a straight line. One train starts frpm A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

(A) 9 a.m.

(B) 10 a.m.

(D) 11 a.m.

View Answer

Ans: B

Suppose they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in (x - 1) hours = 25(x - 1) km.

∴ 20x + 25(x - 1) = 110

⇔ 45x = 135 ⇔ x = 3.

So, they meet at 10 a.m.

1000+ TNPSC Aptitude Study Material in English Pdf - 1

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