100+ Ranking Test Verbal Reasoning Questions & Answers - 1

Ans: C

Let the number of boys be x. Then, number of girls = 2x.
x + 2x = 60 or 3x = 60 or x = 20.
So, number of boys = 20 and number of girls = 40.
Number of students behind Kamal in rank = (60 - 17) = 43.
Number of girls ahead of Kamal in rank = 9.
Number of girls behind Kamal in rank = 40 - 9 = 31.
Number of boys behind Kamal in rank = 43 - 31 = 12.

Ans: B

Three persons A, B, C can be arranged in a queue in six different ways i.e., ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C. So C should be in front of the queue. Thus, there are only two possible arrangements i.e. CBA and CAB.
Clearly number of persons in the queue = ( 3 + 1 + 8 + 1 + 5 + 1 + 21) = 40.
Number of persons between A and C = ( 8 - 6) = 2.
Now, 28 < 40. So, 28 is the minimum number of persons in the queue.

Ans: C

Sumit is 17th from the last and Ravi is 7 ranks ahead of Sumit. So, Ravi is 24th from the last.
Number of students ahead of Ravi in rank = (39 - 24) = 15.
So, Ravi is 16th from the start.

Ans: B

Clearly, number of boys in the line = (11 + 1 + 3) = 15.
Number of boys to be added = 28 - 15 = 13.

Ans: C

Since Kashish and Mona interchange places, So Kashish's new position (13^th from left) is the same as Mona's earlier position (6^th from right).
So, number of children in the queue = (12 + 1 + 5) = 18.
Now, Mona's new position is the same as Kashish's earlier position i.e., fifth from left.
Mona's position from the right = (18 - 4) = 14^th.