100+ SBI PO Quantitative Aptitude Questions with Answers Pdf - 2

Question: 6

What is the least number which when divided by 8, 9, 12 and 15 leaves the same remainder 1 in each case?

(A) 179

(B) 181

(C) 359

(D) 361

Ans: D

Required number = LCM of (8, 9, 12, 15) + 1 = 361.

Question: 7

Six bell commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together?

(A) 4

(B) 10

(C) 15

(D) 16

Ans: D

LCM of 2, 4, 6, 8, 10, 12 is 120.

So, the bells will toll together after every 120 seconds. i.e., 2 minutes. In 30 minutes, they will toll together in $$({30}/{2} + 1)$$ = 16 times.

Question: 8

The H.C.F. of 22 x 33 x 55, 23 x 32 x 52 x 7 and 24 x 34 x 5 x 72 x 11 is

(A) 22 x 32 x 5

(B) 22 x 32 x 5 x 7 x 11

(C) 24 x 34 x 55

(D) 24 x 34 x 55 x 7 x 11

Ans: A

H.C.F. = Product of lowest powers of common factors = 22 × 32 × 5.

Question: 9

Find the greatest number of four digits which when divided by 10, 15, 21 and 28 leaves 4, 9, 15 and 22 as remainders, respectively.

(A) 9654

(B) 9664

(C) 9666

(D) 9864

Ans: A

First, find the greatest number of four digits that is divisible by the L.C.M. of 10, 15, 21 and 28 and then subtract 6 from it to get the required number.

Question: 10

A heap of stones can be made up into groups of 21. When made up into groups of 16, 20, 25 and 45; there are 3 stones left in each case. How many stones at least can there be in the heap?

(A) 2403

(B) 3603

(C) 4803

(D) 7203

Ans: D

L.C.M. of 16, 20, 25, 45 = 3600

1st number = 3600 × 1 + 3 = 3603 which is not divisible by 21.

2nd number = 3600 × 2 + 3 = 7203 which is divisible by 21.

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