Top 100+ Percentage Aptitude Questions with Answers - 1
Question: 1
The price for a pair of cuff links is Rs.1.00. The price for a 5 pair package of cuff links is Rs.3.40. The 5 pair package is what percent cheaper per paid than 5 pairs purchased separately?
(A) 30%
(B) 32%
(C) 47%
(D) 62%
Ans: B
Price of 5 pairs when purchased separately = Rs. 5.
Price of 5 pair package = Rs. 3.40.
Difference in price = Rs. (5 – 3.40) = Rs. 1.60.
Therefore, Required percentage =$$(1.6/ {5} × 100)$$% = 32%.
Question: 2
A city has a population of 3,00,000 out of which 1,80,000 are males. 50% of the population is literate. If 70% of the males are literate, then the percentage of females who are literate is
(A) 10%
(B) 20%
(C) 25%
(D) 30%
Ans: B
Number of males = 180000.
Number of females = (300000 – 180000) = 120000. Number of literates = 50% of 300000 = 150000. Number of literate males = 70% of 180000 = 126000.Number of literate females = (150000 – 126000) = 24000.
Therefore, Required percentage = $$(24000 / {120000} × 100)$$% = 20%.Question: 3
In an examination, 80% of the students passed in English, 85% in Mathematics and 75% in both English and Mathematics. If 40 students failed in both the subjects the total number of students is
(A) 200
(B) 400
(C) 600
(D) 800
Ans: B
Percentage of students failed in both subjects = 100 – (80 + 85 – 75)
= 10%.
10% of students = 40
Therefore, Number of students = 400.
Question: 4
What percentage of numbers from 1 to 70 have squares that end in the digit 1?
(A) 1
(B) 14
(C) 20
(D) 21
Ans: C
Clearly, the numbers which have 1 or 9 in the unit’s digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such numbers = 14.
Therefore, Required percentage = $$(14 / {70} × 100)$$% = 20%.
Question: 5
From 5 litres of a 20% solution of alcohol in water, 2 litres of solution is taken out and 2 litres of water is added to it. Find the strength of alcohol in the news solution.
(A) 10%
(B) 12%
(C) 15%
(D) 18%
Ans: B
Quantity of alcohol in 5 litres solution = 20% of 5 litres = 1 litres.
Quantity of alcohol removed = 20% of 2 litres = 400 ml.
Quantity of alcohol in new solution = (1000 – 400) ml. = 600 ml.
Therefore, Strength of alcohol in new solution = $$(600 / {5000} × 100)$$% = 12%.
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