1000+ Barclays Bank Aptitude Test Questions and Answers Pdf - 1

Ans: B

Putting n = 1, we get (3⁴ⁿ - 4³ⁿ)

= (3⁴ - 4³) = (81 – 64) = 17,

which is divisible by 17.

Ans: B

(2176 - 9) = 2167 = (11 × 197).

So, the required number is 197.

Ans: B

Clearly, (2272 - 875) = 1397, is exactly divisible by N.

Now, 1397 = 11 × 127.

∴ The required 3 digit number is 127, the sum of whose digits is 10.

Ans: C

From 300 to 399, we note that when ‘4’ comes only ‘one’ time = 19 such instances.

From 400 to 499, we note that when ‘4’ comes only one time = 80 such instances.

So, total = (19 + 80) = 99 such instances.

Ans: D

In 978626, we have (6 + 6 + 7) - (2 + 8 + 9) = 0.

Hence, 978626 is completely divisible by 11.