# 1000+ Capgemini Aptitude Questions with Answers Pdf - 1

Question: 1

Given n = 1 + x and x is the product of four consecutive integers. Then which of the following is true?

I. n is odd integer.

II. n is prime

III. n is a perfect square

(A) only I is correct

(B) only III is correct

(C) Both I and II are correct

(D) Both I and III are correct

Ans: D

Out of four consecutive integers two are even and therefore, their product is even and on adding 1 to it, we get an odd integer. So, n is odd. Some possible values of n are as under.

n = 1 + (1 × 2 × 3 × 4) = (1 + 24) = 25 = 5^{2}.

n = 1 + (2 × 3 × 4 × 5) = (1 + 120) = 121 = 11^{2}.

n = 1 + (3 × 4 × 5 × 6) = (1 + 360) = 361 = 19^{2}.

n = 1 + (4 × 5 × 6 × 7) = (1 + 840) = 29^{2} and so on.

Hence, n is odd and a perfect square.

Question: 2

106 × 106 - 94 × 94 = ?

(A) 1904

(B) 1906

(C) 2000

(D) 2400

Ans: D

(106 × 106 - 94 × 94) = (106)^{2} - (94)^{2}

= (106 + 94) (106 - 94) = (200 × 12) = 2400.

Question: 3

Simplify

$${(963 + 476)^2 + (963 – 476)^2} /{ (963 × 963 + 476 × 476)}$$ = ?

(A) 1

(B) 2

(C) 4

(D) 6

Ans: B

Given expression = $${(a + b)^2 + (a - b)}^2/ {(a^2 + b^2)}$$

(where a = 963 and b = 476) = $${2(a^2 + b^2)} / {(a^2 + b^2)}$$ = 2.

Question: 4

In the product 459 × 46 × 28* × 484, the digit in the unit place is 8. The digit to come in place of * is

(A) 3

(B) 5

(C) 7

(D) 9

Ans: A

Unit digit in the given product = 8.

Unit digit of (9 × 6 × x × 4) is 8. So, x = 3.

Question: 5

Evaluate

796 × 796 - 204 × 204 = ?

(A) 392000

(B) 492000

(C) 592000

(D) 692000

Ans: C

796 × 796 - 204 × 204

= (796)^{2} - (204)^{2}
= (796 + 204) (796 - 204) = (1000 × 592) = 592000.

[∴ (a - b)^{2} = (a + b) (a - b)]

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