# 100+ Boats and Streams Questions and Answers for SSC Exams - 1

Question: 1

A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?

(A) 40 minutes

(B) 1 hour

(C) 1 hr 05 min

(D) 1 hr 15 min

Ans: D

Rate downstream = \$\$({1}/{10} × 60)\$\$ km/hr = 6 km/hr.

Rate upstream = 2 km/hr.

Speed in still water = \$\${1}/{2}(6 + 2) \$\$km/hr = 4 km/hr.

∴ Required time = \$\${5}/{4}\$\$ hrs = \$\$1{1}/{4}\$\$ = 1 hr 15 min.

Question: 2

If a man rows at the rate of 5 kmph in still water and his rate against the current is 3.5 kmph, then the man’s rate along the current is

(A) 4.25 kmph

(B) 4.75 kmph

(C) 6 kmph

(D) 6.5 kmph

Ans: D

Let the rate along the current be x kmph.

Then, \$\${1}/{2}(x + 3.5) - 5\$\$ or x = 6.5 kmph.

Question: 3

A swimmer covers a distance of 28 Km against the current and 40 Km in the direction of the current. If in each case he takes 4 hours, then the speed of the current is

(A) 1.5 Km/h

(B) 2.5 Km/h

(C) 3.5 Km/h

(D) 4.5 Km/h

Ans: A

Speed of the swimmer upstream = \$\${28}/{4}\$\$ = 7 Km/h.

Speed of the swimmer downstream = \$\${40}/{4}\$\$ = 10 Km/h.

∴ Speed of the stream

= \$\${1}/{2} (Downstream Speed - Upstream speed)\$\$ = \$\${1}/{2} (10 -7)\$\$ = \$\${3}/{5}\$\$ =1.5 Km/h.

Question: 4

A man can row 6 Km/h in still water. If the river is running at 2 Km/h, it takes 3 hours more in upstream than to go downstream for the same distance. How far is the place?

(A) 22 Km

(B) 24 Km

(C) 28 Km

(D) 32 Km

Ans: B

The required distance

= \$\$({x^2 – y^2)t} / {2y}\$\$ = \$\${(36 - 4)^3} / {2 × 2}\$\$ = 24 km.

Question: 5

A man can row three quarters of a kilometer against the stream in \$\$11{1}/{4}\$\$ minutes. The speed (in km/hr) of the man in still water is

(A) 2

(B) 3

(C) 4

(D) 5

Ans: D

Rate upstream = \$\$({750} / {675})\$\$ m/sec = \$\${10}/{9}\$\$ m/sec.

Rate downstream = \$\${750}/{450}\$\$ m/sec = \$\${5}/{3}\$\$ m/sec.

∴ Rate in still water = \$\${1}/{2} ({10} /{9} + {5}/{3})\$\$ m/sec

= \$\${25}/{18}\$\$ m/sec = \$\$({25} / {18} × {18}/{5})\$\$ km/hr = 5 km/hr.

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