10+ TNPSC Group 4 Previous Year Aptitude Questions and Answers - 1

Question: 1

A man purchased a box full of pencils at the rate of 7 for Rs.9 and sold all of them at the rate of 8 for Rs.11. In this transaction, he gained Rs.10. How many pencils did the box contain?

(A) 100

(B) 101

(D) 116

View Answer

Ans: C

Suppose number of pencils bought = L.C.M. of 7 and 8 =56.

C.P. of 56 pencils = Rs. $$({9}/{7} × 56)$$ = Rs. 72.

S.P. of 56 pencils = Rs. $$({11}/{8} × 56)$$ = Rs. 77.

Now, Rs. 5 are gained on 56 pencils.

So, Rs. 10 are gained on $$({56}/{5} × 10)$$ = 112 pencils.

Question: 2

One variety of sugar is sold for Rs.3.20 per kg at a loss of 20% and another variety is sold for Rs.6 per kg at a gain of 20%. If equal quantities of the two are mixed together and the mixture is sold at Rs.5.40 per kg, what is the loss or gain percentage?

(A) Loss 10%

(B) Gain 10%

(D) Gain 20%

View Answer

Ans: D

C.P. per kg of first variety = Rs. $$({100}/{80} × 3.20)$$ = Rs. 4.

C.P. per kg of second variety = Rs. $$({100}/{120} × 6)$$ = Rs. 5.

C.P. of 2 kg of sugar = Rs. (4 + 5) = Rs. 9.

S.P. pf 2 kg of sugar = Rs. (2 × 5.40) = Rs. 10.80.

Gain = Rs. (10.80 - 9) = Rs. 1.80.

∴ Gain% = $$({1.80} /{9} × 100)$$% = 20%.

Question: 3

Sanket purchased 20 dozen notebooks at Rs.48 per dozen. He sold 8 dozen at 10% profit and the remaining 12 dozen with 20% profit. What is his profit percentage in the transaction?

(A) 12

(B) 16

(D) 19

View Answer

Ans: B

C.P of 20 dozen = Rs. (48 × 20) = Rs. 960.

C.P. of 8 dozen = Rs. (48 × 8) = Rs. 384.

C.P. of 12 dozen = Rs. (960 - 384) = Rs. 576.

Total S.P. = Rs. $$({110}/{100} × 384 + {120}/{100} × 576)$$ = Rs. 1113.60.

∴ Profit % = $$({153.60}/{960} × 100)$$% = 16%.

Question: 4

A shopkeeper offers 2.5% discount on cash purchases. What cash amount would Rohan pay for a cycle, the marked price of which is Rs.650?

(A) Rs. 633.25

(B) Rs. 633.75

(D) Rs. 635

View Answer

Ans: B

S.P. = $$97{1}/{2}$$% of Rs. 650 = Rs. $$({195/2} × {1/100} × 650)$$ = Rs. 633.75.

Question: 5

A vendor loses the selling price of 4 oranges on selling 36 oranges. His loss percent is

(A) 10%

(B) 11%

(D) 13%

View Answer

Ans: A

(C.P. of 36 mangoes) - (S.P. of 36 mangoes)

= Loss = (S.P. of 4 mangoes)

⇒ S.P. of 40 mangoes = C.P. of 36 mangoes.

Let C.P. of each mango be Rs. 1.

C.P. of 40 mangoes = Rs. 40; S.P. of 40 mangoes = Rs. 36.

∴ Loss% = $$({4}/{40} × 100)$$% = 10%.

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10+ TNPSC Group 4 Previous Year Aptitude Questions and Answers - 1

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