Top 100+ Time and Distance Aptitude Questions and Answers - 2

Ans: C

Let distance covered be x in 15 minutes

Average speed = $${Time distance} / {Time taken}$$

                        = $$({650 + 850} / {12 + 18})$$

                        = $$({1500} / {30})$$

                        = 50 kmph.

Ans: D

Speed of Suresh = 10 kmph

Suresh will take rest four times during his journey.

∴ Required time = $$(5 × {1} / {10} × 60)$$minutes + (5 × 4) minutes

= (30 + 20) minutes = 50 minutes.

Suresh takes him to cover a distance of 5 kms.

Ans: B

Speed = $$(600/ 5 × 60)$$ m/sec

          = $$(600 / 5 × 60 × {18} / {5})$$ km/hr

          = 7.2 km/hr.

Ans: C

Total distance covered = (5× 6 + 4 × 12) km

Total time taken = (6 + 12) hours = 18 hours.

∴ Average speed = $$({78}/{18})$$ km/hr = $$4{1} / {3}$$ km/hr.

Ans: C

Distance covered by A in 4 hrs = (4 × 4) km = 16 km.

Relative speed of B w.r.t. A = (10 – 4) = 6 km/hr.

Time taken to cover 16 km at relative speed = $$({16} /{6})$$ hrs = $${8}/{3}$$ hrs.

Distance covered by B in $${8} / {3}$$ hrs = $$(10 × {8} / {3})$$ km = $$({80} / {3})$$ km. = 26.7 km.