# 10,000+ Bank Exam Aptitude Questions and Answers - 1

Question: 1

A train covers a distance of 10 km in 12 minutes. If its speed is decreased by 5 km/hr, the time taken by it cover the same distance will be

(A) 10 min

(B) 13 min

(C) 13 min 20 sec

(D) 13 min 40 sec

Ans: C

Speed = $$(10 × {60}/{12})$$ km/hr = 50 km/hr.

New speed = (50 - 5)km/hr = 45 km/hr.

∴ Time taken = $$({10}/{45})$$hr = $$({2}/{9} × 60)$$min = $$13{1}/{3}$$min = 13 min 20 sec.

Question: 2

A boy rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. His average speed for the entire trip is approximately.

(A) 10.2 km/hr

(B) 10.4 km/hr

(C) 10.8 km/hr

(D) 12.2 km/hr

Ans: C

Total distance travelled = (10 + 12)km/hr = 22 km/hr.

Total time taken = $$({10}/{12} + {12}/{10})$$hrs = $${61}/{30}$$hrs.

∴ Average speed = $$(22 × {30}/{61})$$ km/hr = 10.8 km/hr.

Question: 3

Three persons are walking from a place A to another place B. Their speeds are in the ratio 4 : 3 : 5. The time ratio to reach B by these persons will be

(A) 4 : 3 : 5

(B) 5 : 3 : 4

(C) 15 : 20 : 12

(D) 15 : 24 : 19

Ans: C

Ratio of speeds = 4 : 3 : 5

∴ Ratio of times taken = $${1}/{4}$$ : $${1}/{3}$$ : $${1}/{5}$$ = 15 : 20 : 12.

Question: 4

Reena leaves office at 6.00 p.m. and catches a 6.30 p.m. local train that arrives in her town at 7.00 p.m. Her father leaves home to pick her up at 7.00 p.m. from the station as she gets off the train. Yesterday, Reena left her office early and took a 6.00 p.m. train and arrived at 6.30 p.m. As her father was not there to pick her up, she started walking towards home. Her father left home at the usual time, saw her daughter walking, turned, around, picked her up and drove home, arriving there 10 minutes earlier than the usual. For how long did Reena walk before her father picked her up?

(A) 10 min

(B) 15 min

(C) 25 min

(D) 30 min

Ans: C

Since 10 minutes are saved, it means that Reena’s father drives from the meeting point to the station and back to the meeting point in 10 min i.e. he can drive from the meeting point to the station in $$({10}/{2})$$ = 5 min.

But he reaches the station daily at 7 p.m. So Reena and her father meet on the way at 6 : 55 p.m. Thus, Reena walked for 25 min before her father picked her up.

Question: 5

If Karan travels at a speed of 60 kmph and covers a distance in 9 hrs, then how much time will he take to travel the same distance at a speed of 90 kmph?

(A) 6 hrs

(B) 8 hrs

(C) 9 hrs

(D) 12 hrs

Ans: A

Speed of Karan = 60 kmph

Time = 9 hrs.

Distance = Speed × Time = 60 × 9 = 540 km.

∴ Time taken to cover 540 km at 90 km/ph = $${540} / {90}$$ = 6 hours.

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