1000+ Aptitude Questions and Answers for Placement Papers - 1
Question: 1
A runs $$1{2}/{3}$$ times as fast as B. If A gives B a start of 80 m, how far must the winnings post be so that A and B might reach it at the same time?
(A) 100 m
(B) 200 m
(C) 300 m
(D) 400 m
Ans: B
Ratio of speeds of A and B = $${5}/{3} : 1$$ = 5 : 3.
Thus, in a race of 5m, A gains 2 m over B.
2 m are gained by B in a race of 5 m.
80 m will be gained by B in a race of $$({5}/{2} × 80)$$m = 200 m.
∴ Winning post is 200 m away from the starting point.
Question: 2
In a 800 metre race, A defeated B by 15 seconds. If A’s speed was 8 km/hr, the speed of B was
(A) $${16}/{27}$$ km/hr
(B) $${27}/{16}$$ km/hr
(C) $$6{17}/{25}$$ km/hr
(D) $$7{17}/{25}$$ km/hr
Ans: D
A’s speed = 8 km/hr = $$(8 × {5}/{18})$$ m/sec = $${20}/{9}$$ m/sec.
Time taken by A to cover 800 m = $$(800 × {9}/{20})$$sec = 360 sec.
Time taken by B to cover 800 m (360 + 15) sec = 375 sec.
Speed of B = $${800} / {375}$$ m/sec = $$({800}/{375} × {18}/{5})$$ km/hr = $${192}/{25}$$ km/hr = $$7{17}/{25}$$
Question: 3
In a 100 m race for children, A runs at 1.66 m/s. If A gives B a start of 4 m and still beats him by 12 seconds, what is B’s speed?
(A) 1.33 m/s
(B) 2.33 m/s
(C) 3.33 m/s
(D) 4.33 m/s
Ans: A
Time taken by A to run 100 m = $${100}/{1.66}$$ sec = $${100 × 100}/{166}$$sec = $${5000}/{83}$$ sec.
Time taken by B to run 96 m
= $$({5000} / {83} + 12)$$sec = $$({5000 + 996} / {83})$$sec = $${5996}/{83}$$sec.
B’s speed $$({96 × 83}/{5996})$$m/sec = $$({24 × 83}/{1499})$$m/s = $${1992}/{1499}$$m/s.
= 1.328 m/s = 1.33 m/s.
Question: 4
In a kilometer race, A beats B by 100 m and B beats C by 150 m. In the same race, by how many metres does A beat C?
(A) 225 m
(B) 230 m
(C) 235
(D) 240
Ans: C
A : B = 1000 : 900 and B : C = 1000 : 850.
$${A}/{C}$$ = $${A}/{B} × {B}/{C}$$ = $${1000}/{900} × {1000}/{850}$$ = $${1000}/{765}$$ ⇒ A : C = 1000 : 765.
∴ A beats C by (1000 – 765) m = 235 m.
Question: 5
A and B take part in a 100 m race. A runs at 5 km an hour. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is
(A) 4.14 km/hr
(B) 4.15 km/hr
(C) 4.25 km/hr
(D) 4.45 km/hr
Ans: A
A’s speed = 5 km/hr = $$(5× {5}/{18})$$m/sec = $${25}/{18}$$ m/sec.
Time taken by A to cover 100 m = $$(100 × {18}/{25})$$ sec = 72 sec.
Time taken by B to cover 92 m = (72 + 8) sec = 80 sec.
B’s speed = $$({92}/{80})$$m/sec
= $$({92}/{80} × {18}/{5})$$km/hr = $${414}/{100}$$km/hr = 4.14 km/hr.
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